CODEWITHSUNDEEP
javascript
user1724708
user1724708

Reputation: 1469

JavaScript code is expected to return days of the current week only, but skips the second day

My JavaScript code is expected to return days of the current week only, but skips the second day.

Here is the code:

var curr = new Date;
var first = curr.getDate() - curr.getDay();
var first = first + 1;
var second = first + 2;
var third = first + 3;
var fourth = first + 4;
var fifth = first + 5;
var last = first + 6;

var monday = new Date(curr.setDate(first)).toLocaleDateString();
var tuesday = new Date(curr.setDate(second)).toLocaleDateString();
var wednesday = new Date(curr.setDate(third)).toLocaleDateString();
var thursday = new Date(curr.setDate(fourth)).toLocaleDateString();
var friday = new Date(curr.setDate(fifth)).toLocaleDateString();
var sunday = new Date(curr.setDate(last)).toLocaleDateString();
//alert(monday+" "+sunday)
document.write(monday + " " + tuesday + " " + wednesday + " " + thursday + " " + friday + " " + sunday)

this is my output: 5/13/2019 5/15/2019 5/16/2019 5/17/2019 5/18/2019 5/19/2019 ...notice 5/14/2019 is missing, could I get some help with this please?

Upvotes: 0

Views: 55

Answers (3)

Mister Jojo
Mister Jojo

Reputation: 22334

as day 'zero' is Sunday You may have :

var curr = new Date;
var zero  = curr.getDate() - curr.getDay();   // Sunday - Saturday : 0 - 6
var first  = zero + 1; 
var second = zero + 2;
var third  = zero + 3;
var fourth = zero + 4;
var fifth  = zero + 5;
var last   = zero + 6;


var monday    = new Date(curr.setDate(first)).toLocaleDateString();
var tuesday   = new Date(curr.setDate(second)).toLocaleDateString();
var wednesday = new Date(curr.setDate(third)).toLocaleDateString();
var thursday  = new Date(curr.setDate(fourth)).toLocaleDateString();
var friday    = new Date(curr.setDate(fifth)).toLocaleDateString();
var saturday  = new Date(curr.setDate(last)).toLocaleDateString();


document.write( 'monday.....', monday    , '<br>' )
document.write( 'tuesday....', tuesday   , '<br>' )
document.write( 'wednesday..', wednesday , '<br>' )
document.write( 'thursday...', thursday  , '<br>' )
document.write( 'friday.....', friday    , '<br>' )
document.write( 'saturday...', saturday  , ' ==> ( not sunday ) <br>' )
body { font-family: 'Courier New', Courier, monospace; }

Upvotes: 1

imvain2
imvain2

Reputation: 15857

You are adding 1 to your first day, then incrementing from there incorrectly.

var curr = new Date;
var first = curr.getDate() - curr.getDay();
var monday = new Date(curr.setDate(first+1)).toLocaleDateString();
var tuesday = new Date(curr.setDate(first+2)).toLocaleDateString();
var wednesday = new Date(curr.setDate(first+3)).toLocaleDateString();
var thursday = new Date(curr.setDate(first+4)).toLocaleDateString();
var friday = new Date(curr.setDate(first+5)).toLocaleDateString();
var saturday = new Date(curr.setDate(first+6)).toLocaleDateString();
//alert(monday+" "+sunday)
document.write(monday + " " + tuesday + " " + wednesday + " " + thursday + " " + friday + " " + saturday)

Upvotes: 0

Alex Pakka
Alex Pakka

Reputation: 9706

You are changing first, and then start adding to it.

Consider this code:

var n = 0;
var n = n+1;
var n2 = n+2;

you will end up with n == 1 and n2 == 3.

Also, if you were using let instead of var, JavaScript would have caught this error for you.

Upvotes: 0

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