CODEWITHSUNDEEP
typescript
makmav
makmav

Reputation: 65

Typescript compiled file cannot find module

I have an exported module in one file(parser.js) in Typescript project and I did not generate any error during the compilation phase ,but the Compiled file can't work, This makes me feel confused

// parser.d.ts
declare module 'parser' {
    interface Parser {
        parser(url: string):string
    }

    export class UrlParser implements Parser {
        parser(url: string): string  {
            return  url.includes('https') ? url.replace('https', 'http') : '';
        }
    }
}

// parser.js
export default class UrlParser {
    parser(url)  {
        return  url.includes('https') ? url.replace('https', 'http') : '';
    }
}

/// <reference path="../lib/parser.d.ts" />
import * as Parser  from 'parser';

let urlParser = new Parser.UrlParser()
console.log(urlParser.parser('https://www.baidu.com'))

// compiled file I got
"use strict";
var __importStar = (this && this.__importStar) || function (mod) {
    if (mod && mod.__esModule) return mod;
    var result = {};
    if (mod != null) for (var k in mod) if (Object.hasOwnProperty.call(mod, k)) result[k] = mod[k];
    result["default"] = mod;
    return result;
};
Object.defineProperty(exports, "__esModule", { value: true });
/// <reference path="../lib/parser.d.ts" />
var Parser = __importStar(require("parser"));
var urlParser = new Parser.UrlParser();
console.log(urlParser.parser('https://www.baidu.com'));

I got an error when I executed the node ./dest/main/js command.

Error: Cannot find module 'parser'

Upvotes: 4

Views: 2917

Answers (1)

Robbie Milejczak
Robbie Milejczak

Reputation: 5770

You should use a relative path (e.g. './dest/lib/parser') in that import statement since by default require is going to look in node_modules if a path is not passed (where as TypeScript can be told where 'parser' is).

You could also add a package.json file to the same folder as parser.js with the contents { name: 'parser' } which would allow it to be found via require('parser')

Upvotes: 1

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