CODEWITHSUNDEEP
pythonregexweb-scraping
Aziza Sbai El Idrissi
Aziza Sbai El Idrissi

Reputation: 81

IndexError: list index out of range with Regular expression

I am trying to scrape data from this link https://www.seloger.com/ and I get this error, I don't understand what's wrong because I already tried this code before and it worked

import re
import requests
import csv
import json


with open("selog.csv", "w", newline="") as f:
writer = csv.writer(f)
writer.writerow(["id", "Type", "Prix", "Code_postal", "Ville", "Departement", "Nombre_pieces", "Nbr_chambres", "Type_cuisine", "Surface"]) 


for i in range(1, 500):
   url = str('https://www.seloger.com/list.htm?tri=initial&idtypebien=1,2&pxMax=3000000&div=2238&idtt=2,5&naturebien=1,2,4&LISTING-LISTpg=' + str(i))
   r = requests.get(url, headers = {'User-Agent' : 'Mozilla/5.0'})
   p = re.compile('var ava_data =(.*);\r\n\s+ava_data\.logged = logged;', re.DOTALL)
   x = p.findall(r.text)[0].strip().replace('\r\n    ','').replace('\xa0',' ').replace('\\','\\\\')
   x = re.sub(r'\s{2,}|\\r\\n', '', x)
   data = json.loads(x)
   f = csv.writer(open("Seloger.csv", "wb+"))


   for product in data['products']:
      ID = product['idannonce']
      prix = product['prix']
      surface = product['surface']
      code_postal = product['codepostal']
      nombre_pieces = product['nb_pieces']
      nbr_chambres = product['nb_chambres']
      Type = product['typedebien']
      type_cuisine = product['idtypecuisine']
      ville = product['ville']
      departement = product['departement']
      etage = product['etage']
      writer.writerow([ID, Type, prix, code_postal, ville, departement, nombre_pieces, nbr_chambres, type_cuisine, surface])

this the error :

Traceback (most recent call last):
File "Seloger.py", line 20, in <module>
x = p.findall(r.text)[0].strip().replace('\r\n    ','').replace('\xa0',' ').replace('\\','\\\\')
IndexError: list index out of range

Upvotes: 0

Views: 1860

Answers (2)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626691

The error occurs because sometimes there is no match, and you are trying to access a non-existing item in an empty list. The same result can be reproduced with print(re.findall("s", "d")[0]).

To fix the issue, replace x = p.findall(r.text)[0].strip().replace('\r\n ','').replace('\xa0',' ').replace('\\','\\\\') line with

x = ''
xm = p.search(r.text)
if xm:
    x = xm.group(1).strip().replace('\r\n    ','').replace('\xa0',' ').replace('\\','\\\\')

NOTES

  • When you use p.findall(r.text)[0], you want to get the first match in the input, so re.search is best here as it only returns the first match
  • To obtain the substirng captured in the first capturing group, you need to use matchObject.grou[p(1)
  • if xm: is important: if there is no match, x will remain an empty string, else, it will be assigned the modified value in Group 1.

Upvotes: 0

user7313188
user7313188

Reputation:

This line is wrong:

x = p.findall(r.text)[0].strip().replace('\r\n    ','').replace('\xa0',' ').replace('\\','\\\\')

what you need to find in text?

for working scraped on text you need change above line to:

x = r.text.strip().replace('\r\n    ','').replace('\xa0',' ').replace('\\','\\\\')

and then finding something you need

Upvotes: 1

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