CODEWITHSUNDEEP
node.jspuppeteer
Rohit
Rohit

Reputation: 1533

Page.evaluate() returns undefined, but statement works in Chrome devTools

I'm trying to get the src values for all images on Bing image search for a search term. I am using puppeteer for it. I wrote a selector to grab each image tag and it works in the Chrome DevTools. It, however, isn't working when I write it in the code-

const puppeteer = require("puppeteer");

(async () => {
    try{
        let url = `https://www.bing.com/images/search?q=cannabis`
        const browser = await puppeteer.launch({headless: false})
        const page = await browser.newPage()
        await page.goto(url)
        await page.waitForSelector("ul.dgControl_list li img.mimg")

        console.log(await page.evaluate(() => {
            Array.from(document.querySelectorAll("ul.dgControl_list>li img.mimg"), img => img.src)
        }))
    } catch(err){
        console.log("error - " + err)
    }
})()

I get the output as an object containing arrays of 10 items each in the devTools, but when I run it in the console through my code, it is undefined. How do I read this object?

Upvotes: 1

Views: 5483

Answers (1)

Thomas Dondorf
Thomas Dondorf

Reputation: 25230

You are not returning any data from the page.evaluate call. To return the data you have to use the return statement or use the short syntax (as explained below):

console.log(await page.evaluate(() => {
    return Array.from(document.querySelectorAll("ul.dgControl_list>li img.mimg"), img => img.src)
}))

Explanation: Arrow function

The arrow function has two ways to write them. One is the short syntax, you can use it like this:

const func = () => 1; // func() will simply return 1

You can only put in one statement in there (which might call other statements though). Alternatively, you can use the long form:

const func = () => { return 1; }; // Same function as above

You can use variable declarations and any kind of code inside this function (just as in a normal function() { ... }, but this time you have to use return to return a value.

Therefore, as an alternative, you could also write this (short syntax):

console.log(await page.evaluate(
    () => Array.from(document.querySelectorAll("ul.dgControl_list>li img.mimg"), img => img.src)
))

Upvotes: 1

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