CODEWITHSUNDEEP
pythonfunctionhttpcallback
felartu
felartu

Reputation: 92

How to pass arguments to a callback function in Python?

I want to make my code Async for HTTP calls, since the whole program stops while the call is being made.

I took a look at grequests and couldn't figure it out, same for asyncio

this is the current sync version of the code:

myvar1 = class_object()

response = requests.get(myvar1.url)

if response.status_code == 200:
    myvar1.accept()

I would like to do the following instead:

def myfunction:

    request.get(myvar1.url,callbackfunction(response,myvar1))

    return None

def callbackfunction(response,myvar1):

    if response.status_code == 200:
        myvar1.accept()

I can successfully pass a callback function to the request, the question is how to pass arguments to that callback.

Basically, the goal is to execute a method of the passed argument of the callback function.

Upvotes: 3

Views: 2540

Answers (1)

quamrana
quamrana

Reputation: 39414

Lets make a partial function:


def myfunction(var, func):

    request.get(var.url, callback =  func)


def callbackfunction(response, var):

    if response.status_code == 200:
        var.accept()

# Now make a partial function to wrap callbackfunction
def wrapper(var):
    def callback(response):
        callbackfunction(response, var)
    return callback

myvar1 = class_object()

myfunction(myvar1, wrapper(myvar1))

So, requests.get() will eventually call func(response) which in fact will be callback(response) which calls callbackfunction(response, myvar1)

Upvotes: 4

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