CODEWITHSUNDEEP
pythonsqlalchemy
dropWizard
dropWizard

Reputation: 3538

SqlAlchemy getting model name from object

I have an object that I'm passing to a queue to write to a database. I need to perform some logic checks to handle errors:

How can I check to see which model that object is? 

c = Candidate(....)

type(c)
<class 'models.Candidate'>

is there anyway I can access Candidates in an if statement? 

if type(c)... == 'Candidate':

I realize I can just do:

if type(c) == <class 'models.Candidate'> but didn't know if there was a cleaner way

Upvotes: 1

Views: 2761

Answers (3)

gachdavit
gachdavit

Reputation: 1261

If you want to check type of object,,, You can do like this,,,

class Foo:
  pass
f = Foo()
print(isinstance(f, Foo)) # True
print(type(f) is Foo) # True (also use == possible)
print(f.__class__ is Foo) # True (also use == possible)

isinstance(obj, type) # this works also on subclasses.
class Boo(Foo):
   pass
b = Boo()
isinstance(b, Foo) # True

Upvotes: 0

Amine Messaoudi
Amine Messaoudi

Reputation: 2279

There are two ways :

1) - By class name

def get_class_name(variable)
    return type(variable).__class__.__name__

var = "Hello"
if get_class_name(var) == 'str':
    ...

2) - By using isinstance

var = "Hello"
if isinstance(var, str):
    ....

Upvotes: 1

Simon Fraser
Simon Fraser

Reputation: 2818

How about isinstance?

if isinstance(c, models.Candidate):

This will return True if c is an instance of models.Candidate or an instance of a subclass.

You'll occasionally see functions that check to see what types they've received, such as: if isinstance(arg1, str): or if isinstance(arg1, list):

Upvotes: 1

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