Reputation: 2821
I was trying to attach a csv
file as a body parameter in my test script. But still as per the below code controller expect file and just curious how should I pass that.
I run test script in below order
Method-1
public void AttachedRatesFile(string fileName)
{
_form = string.IsNullOrWhiteSpace(fileName)
? _form = new StringContent(string.Empty)
: _form = new StreamContent(File.OpenRead($"{ResourceFolder}{fileName}"));
_form.Headers.ContentType = new MediaTypeHeaderValue("application/csv");
_form.Headers.ContentDisposition = new ContentDispositionHeaderValue(fileName);
}
Method-2
public void PostRequestExecutes(string resource)
{
var content = new MultipartFormDataContent{_form};
WhenThePostRequestExecutesWithContent(resource, content);
}
Method-3
public async void WhenThePostRequestExecutesWithContent(string resource, HttpContent content)
{
ResponseMessage = await HttpClient.PostAsync(resource, content);
}
I see null in below file parameter
Controller:
public async Task<IActionResult> SeedData(IFormFile file)
{
var result = await _seedDataService.SeedData(file);
return Ok(new { IsUploadSuccesful = result});
}
Upvotes: 0
Views: 2218
Reputation: 705
I would add that to the body as a stream
var memoryContentStream = new MemoryStream();
using (var streamWriter = new StreamWriter(memoryContentStream, Encoding.UTF8, 1000,
true))
{
using (var jsonTextWriter = new JsonTextWriter(streamWriter))
{
var jsonSerializer = new JsonSerializer();
jsonSerializer.Serialize(jsonTextWriter, OBJECT);
jsonTextWriter.Flush();
}
}
if (memoryContentStream.CanSeek)
{
memoryContentStream.Seek(0, SeekOrigin.Begin);
}
Then
using (var streamContent = new StreamContent(memoryContentStream))
{
streamContent.Headers.ContentType = new MediaTypeHeaderValue("application/json");
request.Content = streamContent;
using (var response = await _httpClient.SendAsync(request, HttpCompletionOption.ResponseHeadersRead))
{
var stream = await response.Content.ReadAsStreamAsync();
response.EnsureIsSuccessStatusCode();
}
}
The above would first write the content as a memory stream and then when creating the POST request you can send the stream as a streamContent
Upvotes: 1