CODEWITHSUNDEEP
javascriptarraysobject
ReNinja
ReNinja

Reputation: 573

Count the occurence of each words in a string and put it in an object

I need to get the total count of each word in a string .

I wanted to achieve it using reducer since i am a beginner in the reduce method i could not solve it .

getWordOccurence = (str1) => {
  splitStr = str1.split(' ');
  let count=0;
  const wordCount = splitStr.reduce((acc, curr) => ({...acc,[curr]:count}),{})
  console.log(wordCount)
};

getWordOccurence('apple orange apple banana grapes ?');

Expected : {"apple":2,"orange":1,"banana":1,"grape":1}

Upvotes: 1

Views: 81

Answers (3)

Yosvel Quintero
Yosvel Quintero

Reputation: 19070

You can String.prototype.split() the string and use Array.prototype.reduce() to obtain the result object

In case you need to exclude the non words you can do Regular Expression /[a-z]/i to check the String.prototype.match() c.match(/[a-z]/i)

Code:

const str = 'apple orange apple banana grapes ?';
const getWordOccurence = s => s.split(' ').reduce((a, c) => {
  if (c.match(/[a-z]/i)) { // Only words...
    a[c] = (a[c] || 0) + 1;
  }
  return a;
}, {});
const result = getWordOccurence(str);

console.log(result);

Upvotes: 0

apple apple
apple apple

Reputation: 10591

I'd like to post a pure reducer version.

const getWordOccurence = (str1) => {
  const splitStr = str1.split(' ');
  const wordCount = splitStr.reduce((acc, x)=>({...acc,[x]:acc[x]+1||1}),{})
  console.log(wordCount)
};

getWordOccurence('apple orange apple banana grapes ?');

otherwise, I recommend simply use accumulator and loop through object (you can always extract it to a function, like occurence or something, you don't even need to pass the {} then).

const getWordOccurence = (str1) => {
  const words = str1.split(' ');
  
  //function occurence(words){
  let acc={};
  for(let word of words)
    acc[word] = acc[word]+1 || 1
  //return acc}
  
  //const wordCount = occurence(words)
  const wordCount = acc //just in case you want a *const* result
  
  console.log(wordCount)
};

getWordOccurence('apple orange apple banana grapes ?');

Upvotes: 0

Maheer Ali
Maheer Ali

Reputation: 36564

You can try using comma operator. I thinks its better to use comma operator to return accumulator rather than using spread operator.

const getWordOccurence = (str1) => {
  splitStr = str1.split(' ');
  const wordCount = splitStr.reduce((ac, x) => (ac[x] = ac[x] + 1 || 1,ac),{})
  console.log(wordCount)
};

getWordOccurence('apple orange apple banana grapes ?');

One line for the function will be 

const getWordOccurence = (str) => str.split(' ').reduce((ac,a) => (ac[a] = ac[a] + 1 || 1,ac),{})

console.log(getWordOccurence('apple orange apple banana grapes ?'));

Upvotes: 2

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