CODEWITHSUNDEEP
javascriptstringloopsreturnslice
PineNuts0
PineNuts0

Reputation: 5234

JavaScript: Loop through string and return string + 'ay' if string contains vowel in first letter

I am trying to run a function that does pig latin. I'm stuck on one of the first steps.

When I set the input argument equal to 'eat' => I want my code to return the string plus 'ay'. Please see code below for if statement as well.

Instead, when I run my code it returns undefined. I want it to return 'eatay'. Why? 

// Pig Latin

const pigify = (str) => {

  let sentSplit = str.split(' ')
  //console.log(sentSplit)

  for (let i=0; i<sentSplit.length; i++){
    //console.log(sentSplit[i])
    let element = sentSplit[i]

    console.log(element[0])

    if (element[0].includes('a', 'e', 'i', 'o', 'u')){
      return `${element}ay`
    }

    // else if (!str[0].includes('a', 'e', 'i', 'o', 'u') && !str[1].includes('a', 'e', 'i', 'o', 'u')){
    //   return `${str.slice(2)}${str.slice(0,2)}ay`
    // }

    // else if(!str[0].includes('a', 'e', 'i', 'o', 'u')){
    //   return `${str.slice(1)}${str[0]}ay`
    // }
  }
}

pigify('eat')

Upvotes: 0

Views: 97

Answers (2)

Pavithra Ravichandran
Pavithra Ravichandran

Reputation: 55

JavaScript itself provides the functions 'includes' and 'charAt'. Instead of splitting the string to characters array and finding the first element, str.charAt(0) can be used. and includes function searches through the array and returns true if any element matches.

const pigify = (str) => {
  if(['a', 'e', 'i', 'o', 'u'].includes(str.charAt(0))) {
  return str+'ay';
}

Upvotes: 1

Barmar
Barmar

Reputation: 782148

You have the arguments to includes() wrong. The syntax is container.includes(element), so it should be:

if (['a', 'e', 'i', 'o', 'u'].includes(element[0])) {

Upvotes: 2

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