CODEWITHSUNDEEP
arraysjenkinsgroovy
SSF
SSF

Reputation: 983

Retrieve Index of a an Element in an Array of Arrays in Groovy

I have an array of arrays. 

def my_array = [[null], [10382], [11901], [null], [10386], [10385], [11901], [10386], [11901], [10386], [3], [null], [10504], [3]]

I want to find the index of the FIRST occurrence of an element, for example [3].

I am using findIndexOf. 

 def index = my_array.findIndexOf { it == [3] }

However, this returns -1. I think this is the index of the element in array [3] not in array my_array. How do I get the index of the element [3] in the my_array?

Upvotes: 2

Views: 10126

Answers (1)

Matias Bjarland
Matias Bjarland

Reputation: 4482

Running this code: 

def my_array = [[null],  // index  0
                [10382], // index  1
                [11901], // index  2
                [null],  // index  3
                [10386], // index  4
                [10385], // index  5
                [11901], // index  6
                [10386], // index  7
                [11901], // index  8
                [10386], // index  9
                [3],     // index 10
                [null],  // index 11
                [10504], // index 12
                [3]]     // index 13

def index = my_array.findIndexOf { it == [3] }
println "index: $index"

which is identical to your code results in: 

~> groovy solution.groovy 
index: 10

~>

on java 8 and groovy 2.1.16. In other words, your code should work.

As a side note, do you really need a list of lists? As all the lists are of length one you might as well just have a list of elements directly.

Upvotes: 4

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