CODEWITHSUNDEEP
pythonregexregex-groupcjkregex-greedy
GoBackess
GoBackess

Reputation: 414

RegEx for capturing Korean alphabets

My data frame in name is like below:

'가락시장(340)',
'가락시장(8)',
'가산디지털단지(7)',
'강남(222)',
'강남구청',
'강동',
'강동구청',
'강변(214)',
'개롱',
'개화산',
'거여',
'건대입구(212)',
'건대입구(7)',
'경복궁(317)',
'경찰병원(341)',
'고덕',
'고려대',
'고속터미널(329)',
'고속터미널(7)',
'공덕(5)',
'공덕(6)',
'공릉',
'광나루',
...

All list is in this link

Desired Output:

가락시장
가산디지털단지
강남
강남구청
강동
강동구청
강변
개롱
개화산
거여
건대입구
경복궁
경찰병원
고덕
고려대
고속터미널
공덕
공릉
광나루

Attempt

import re

for i in df['name']:
    i = re.match('^[가-힣]*$', i) # '^[가-힣]&$ is extract Hangeul (Korean alphabet)

But df['name'] does not change.

How do I solve this problem?

Upvotes: 1

Views: 2072

Answers (2)

john
john

Reputation: 56

You can remove parentheses and parenthesized characters with the following code:

import re
pattern = re.compile(r'\(\w*\)')
for text in YOUR_DATA_LIST : 
    only_station_name = re.sub(pattern, '', text)
    print(only_station_name)

Upvotes: 0

Emma
Emma

Reputation: 27743

We might be able to capture your desired output with a simple expression, with only a ' as a left boundary, then collecting the letters, similar to: 

'([\p{L}]+)

Test

# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility

import re

regex = r"'([\p{L}]+)"

test_str = ("'가락시장(340)',\n"
    " '가락시장(8)',\n"
    " '가산디지털단지(7)',\n"
    " '강남(222)',\n"
    " '강남구청',\n"
    " '강동',\n"
    " '강동구청',\n"
    " '강변(214)',\n"
    " '개롱',\n"
    " '개화산',\n"
    " '거여',\n"
    " '건대입구(212)',\n"
    " '건대입구(7)',\n"
    " '경복궁(317)',\n"
    " '경찰병원(341)',\n"
    " '고덕',\n"
    " '고려대',\n"
    " '고속터미널(329)',\n"
    " '고속터미널(7)',\n"
    " '공덕(5)',\n"
    " '공덕(6)',\n"
    " '공릉',\n"
    " '광나루',")

matches = re.finditer(regex, test_str, re.MULTILINE)

for matchNum, match in enumerate(matches, start=1):

    print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))

    for groupNum in range(0, len(match.groups())):
        groupNum = groupNum + 1

        print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))

# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.

enter image description here

RegEx

If this expression wasn't desired, it can be modified or changed in regex101.com.

RegEx Circuit

jex.im visualizes regular expressions:

Reference

How to implement \p{L} in python regex

Upvotes: 1

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