Reputation: 1315
I am trying to replace values from two columns with values from another two columns. This is a rather basic question and has been asked by python
users, however I am using R.
I have a df
that looks like this (only on a much larger scale [>20,000]):
squirrel_id locx locy dist
6391 17.5 10.0 50.0
6391 17.5 10.0 20.0
6391 17.5 10.0 15.5
8443 20.5 1.0 800
6025 -5.0 -0.5 0.0
I need to, for 63 squirrels, replace their locx
and locy
values.
I normally replace values with the following code:
library(dplyr)
df <- df %>%
mutate(locx = ifelse (squirrel_id=="6391", "12.5", locx),
locy = ifelse (squirrel_id=="6391", "15.5", locy),
locx = ifelse (squirrel_id=="8443", "2.5", locx),
locy = ifelse (squirrel_id=="8443", "80", locy)) #etc for 63 squirrels
Which would give me:
squirrel_id locx locy dist
6391 12.5 10.0 50.0
6391 12.5 10.0 20.0
6391 12.5 10.0 15.5
8443 2.5 80.0 800
6025 -5.0 -0.5 0.0
But this is creating an extra 126 lines of code and I suspect there is a simpler way to do this.
I do have all the new locx
and locy
values in a separate df
, but I do not know how to join the two dataframe
s by squirrel_id
without it messing up the data.
df
with the values that need to replace the ones in the old df
:
squirrel_id new_locx new_locy
6391 12.5 15.5
8443 2.5 80
6025 -55.0 0.0
How can I do this more efficiently?
Upvotes: 0
Views: 332
Reputation: 11255
Using @ANG's data, here's a data.table
solution. It joins and updates the original df
by reference.
library(data.table)
setDT(df)
setDT(df2)
df[df2, on = c('squirrel_id'), `:=` (locx = new_locx, locy = new_locy) ]
df
squirrel_id locx locy dist
1: 6391 12.5 15.5 50.0
2: 6391 12.5 15.5 20.0
3: 6391 12.5 15.5 15.5
4: 8443 2.5 80.0 800.0
5: 6025 -55.0 0.0 0.0
6: 5000 18.5 12.5 10.0
See also:
how to use merge() to update a table in R
Replace a subset of a data frame with dplyr join operations
R: Updating a data frame with another data frame
Upvotes: 0
Reputation: 6768
You can left_join
the two data frames and then use an if_else
statement to get the right locx
and locy
. Try out:
library(dplyr)
df %>% left_join(df2, by = "squirrel_id") %>%
mutate(locx = if_else(is.na(new_locx), locx, new_locx), # as suggested by @echasnovski, we can also use locx = coalesce(new_locx, locx)
locy = if_else(is.na(new_locy), locy, new_locy)) %>% # or locy = coalesce(new_locy, locy)
select(-new_locx, -new_locy)
# output
squirrel_id locx locy dist
1 6391 12.5 15.5 50.0
2 6391 12.5 15.5 20.0
3 6391 12.5 15.5 15.5
4 8443 2.5 80.0 800.0
5 6025 -55.0 0.0 0.0
6 5000 18.5 18.5 10.0 # squirrel_id 5000 was created for an example of id
# present if df but not in df2
Data
df <- structure(list(squirrel_id = c(6391L, 6391L, 6391L, 8443L, 6025L,
5000L), locx = c(17.5, 17.5, 17.5, 20.5, -5, 18.5), locy = c(10,
10, 10, 1, -0.5, 12.5), dist = c(50, 20, 15.5, 800, 0, 10)), class = "data.frame", row.names = c(NA,
-6L))
df2 <- structure(list(squirrel_id = c(6391L, 8443L, 6025L), new_locx = c(12.5,
2.5, -55), new_locy = c(15.5, 80, 0)), class = "data.frame", row.names = c(NA,
-3L))
Upvotes: 1