Reputation: 341
I've got a directory with a bunch of files. Instead of describing the filenames and extensions, I'll just show you what is in the directory:
P01_1.atag P03_3.tgt P05_6.src P08_3.atag P10_5.tgt
P01_1.src P03_4.atag P05_6.tgt P08_3.src P10_6.atag
P01_1.tgt P03_4.src P06_1.atag P08_3.tgt P10_6.src
P01_2.atag P03_4.tgt P06_1.src P08_4.atag P10_6.tgt
P01_2.src P03_5.atag P06_1.tgt P08_4.src P11_1.atag
P01_2.tgt P03_5.src P06_2.atag P08_4.tgt P11_1.src
P01_3.atag P03_5.tgt P06_2.src P08_5.atag P11_1.tgt
P01_3.src P03_6.atag P06_2.tgt P08_5.src P11_2.atag
P01_3.tgt P03_6.src P06_3.atag P08_5.tgt P11_2.src
P01_4.atag P03_6.tgt P06_3.src P08_6.atag P11_2.tgt
P01_4.src P04_1.atag P06_3.tgt P08_6.src P11_3.atag
P01_4.tgt P04_1.src P06_4.atag P08_6.tgt P11_3.src
P01_5.atag P04_1.tgt P06_4.src P09_1.atag P11_3.tgt
P01_5.src P04_2.atag P06_4.tgt P09_1.src P11_4.atag
P01_5.tgt P04_2.src P06_5.atag P09_1.tgt P11_4.src
P01_6.atag P04_2.tgt P06_5.src P09_2.atag P11_4.tgt
P01_6.src P04_3.atag P06_5.tgt P09_2.src P11_5.atag
P01_6.tgt P04_3.src P06_6.atag P09_2.tgt P11_5.src
P02_1.atag P04_3.tgt P06_6.src P09_3.atag P11_5.tgt
P02_1.src P04_4.atag P06_6.tgt P09_3.src P11_6.atag
P02_1.tgt P04_4.src P07_1.atag P09_3.tgt P11_6.src
P02_2.atag P04_4.tgt P07_1.src P09_4.atag P11_6.tgt
P02_2.src P04_5.atag P07_1.tgt P09_4.src P12_1.atag
P02_2.tgt P04_5.src P07_2.atag P09_4.tgt P12_1.src
P02_3.atag P04_5.tgt P07_2.src P09_5.atag P12_1.tgt
P02_3.src P04_6.atag P07_2.tgt P09_5.src P12_2.atag
P02_3.tgt P04_6.src P07_3.atag P09_5.tgt P12_2.src
P02_4.atag P04_6.tgt P07_3.src P09_6.atag P12_2.tgt
P02_4.src P05_1.atag P07_3.tgt P09_6.src P12_3.atag
P02_4.tgt P05_1.src P07_4.atag P09_6.tgt P12_3.src
P02_5.atag P05_1.tgt P07_4.src P10_1.atag P12_3.tgt
P02_5.src P05_2.atag P07_4.tgt P10_1.src P12_4.atag
P02_5.tgt P05_2.src P07_5.atag P10_1.tgt P12_4.src
P02_6.atag P05_2.tgt P07_5.src P10_2.atag P12_4.tgt
P02_6.src P05_3.atag P07_5.tgt P10_2.src P12_5.atag
P02_6.tgt P05_3.src P07_6.atag P10_2.tgt P12_5.src
P03_1.atag P05_3.tgt P07_6.src P10_3.atag P12_5.tgt
P03_1.src P05_4.atag P07_6.tgt P10_3.src P12_6.atag
P03_1.tgt P05_4.src P08_1.atag P10_3.tgt P12_6.src
P03_2.atag P05_4.tgt P08_1.src P10_4.atag P12_6.tgt
P03_2.src P05_5.atag P08_1.tgt P10_4.src
P03_2.tgt P05_5.src P08_2.atag P10_4.tgt
P03_3.atag P05_5.tgt P08_2.src P10_5.atag
P03_3.src P05_6.atag P08_2.tgt P10_5.src
I have a file that is just outside of this directory that I need to copy to all of the files that end with "_1.src" inside the directory.
I'm working with unix in the Terminal app, so I tried writing this for loop, but it rejected my regular expression:
for .*1.src in ./
> do
> cp ../1.src
> done
I've only written regular expressions in Python before and have minimal experience, but I was under the impression that .* would match any combination of characters. However, I got the following error message:
-bash: `.*1.src': not a valid identifier
I then tried the same for loop with the following regular expression:
^[a-zA-Z0-9_]*1.src$
But I got the same error message:
-bash: `^[a-zA-Z0-9_]*1.src$': not a valid identifier
I tried the same regular expression with and without quotation marks, but it always gives the same 'not a valid identifier' error message.
Upvotes: 1
Views: 411
Reputation: 341
Thanks to everyone; this is what ended up working:
for x in `echo ./P[0-9]*_1.src`
> do
> cp ../1.src "$x"
> done
This loop allowed me to copy the contents of the one file to all of the files in the subdirectory that ended with "_1.src"
Upvotes: 1
Reputation: 2030
Please correct me if your goal is something other than
"overwrite many existing files sharing a common suffix with the contents of a single file"
find /path/to/dest_dir -type f -name "*_1.src" |xargs -n1 cp /path/to/source_file
Note that without the -maxdepth 1
option, find
will recurse through your destination directory.
Upvotes: 0
Reputation: 3441
Tested on Bash 4.4.12, the following is possible:
$ for i in ./*_1.src; do echo "$i" ; done
This will echo every file ending with _1.src
to the screen, thus moving it will be possible as well.
$ mkdir tmp
$ for i in ./*_1.src; do mv "$i" tmp/.; done
I've tested with the following data:
$ touch P{1,2}{0,1,2}_{0..6}.{src,tgt,atag}
$ ls
P10_0.atag P10_5.src P11_3.tgt P12_2.atag P20_0.src P20_5.tgt P21_4.atag P22_2.src
P10_0.src P10_5.tgt P11_4.atag P12_2.src P20_0.tgt P20_6.atag P21_4.src P22_2.tgt
P10_0.tgt P10_6.atag P11_4.src P12_2.tgt P20_1.atag P20_6.src P21_4.tgt P22_3.atag
P10_1.atag P10_6.src P11_4.tgt P12_3.atag P20_1.src P20_6.tgt P21_5.atag P22_3.src
P10_1.src P10_6.tgt P11_5.atag P12_3.src P20_1.tgt P21_0.atag P21_5.src P22_3.tgt
P10_1.tgt P11_0.atag P11_5.src P12_3.tgt P20_2.atag P21_0.src P21_5.tgt P22_4.atag
P10_2.atag P11_0.src P11_5.tgt P12_4.atag P20_2.src P21_0.tgt P21_6.atag P22_4.src
P10_2.src P11_0.tgt P11_6.atag P12_4.src P20_2.tgt P21_1.atag P21_6.src P22_4.tgt
P10_2.tgt P11_1.atag P11_6.src P12_4.tgt P20_3.atag P21_1.src P21_6.tgt P22_5.atag
P10_3.atag P11_1.src P11_6.tgt P12_5.atag P20_3.src P21_1.tgt P22_0.atag P22_5.src
P10_3.src P11_1.tgt P12_0.atag P12_5.src P20_3.tgt P21_2.atag P22_0.src P22_5.tgt
P10_3.tgt P11_2.atag P12_0.src P12_5.tgt P20_4.atag P21_2.src P22_0.tgt P22_6.atag
P10_4.atag P11_2.src P12_0.tgt P12_6.atag P20_4.src P21_2.tgt P22_1.atag P22_6.src
P10_4.src P11_2.tgt P12_1.atag P12_6.src P20_4.tgt P21_3.atag P22_1.src P22_6.tgt
P10_4.tgt P11_3.atag P12_1.src P12_6.tgt P20_5.atag P21_3.src P22_1.tgt P10_5.atag
P11_3.src P12_1.tgt P20_0.atag P20_5.src P21_3.tgt P22_2.atag
Upvotes: 1
Reputation: 44838
Apparently, my previous answer didn't work. But this seems to:
$ for x in `echo ./P[01][012]_1.src`; do echo "$x"; done
./P01_1.src
./P02_1.src
So, when you run this echo
alone, this pattern gets expanded into many names:
$ echo ./P[01][012]_1.src # note that the 'regex' is not enclosed in quotes
./P01_1.src ./P02_1.src
And then you can iterate over these names in a loop.
BTW, as noted in the comments, you don't even need that echo
, so you can plug the pattern right into the loop:
for x in ./P[01][012]_1.src; do echo "$x"; done
Upvotes: 0