CODEWITHSUNDEEP
ruby
fxtest qwerty
fxtest qwerty

Reputation: 11

Get values from nested hash

I have this Hash that I use store values and if the values are not found to get default values:

AMOUNT = {
  EUR: {
    eps:         { AT: 1_00 },
    safetypay:   { PE: 15_000_00, CR: 5_000_00, BE: 15_000_00, },
    przelewy24:  5_00,
    qiwi:        5_00,
    bcmc:        { AT: 1_00, BE: 1_00 },
    giropay:     { DE: 1_00 },
    ideal:       { NL: 1_00 },
    mybank:      { IT: 1_00, FR: 1_00 },
  },
  CZK: {
    trustpay:   { CZ: 20_00 }
  }
}.with_indifferent_access

I would like to get values based on the keys so I tried this:

def amount_for(payment_type, country, currency)
  payment_amount = AMOUNT.dig(currency, payment_type, country) if payment_type.is_a?(Hash)
  payment_amount ||= AMOUNT.dig(currency, payment_type)
  payment_amount ||= 1
end

But I get for result not number but {"AT"=>100, "BE"=>100}. If I remove the check if payment_type.is_a?(Hash) I get exception Integer does not have #dig method (RuntimeError)

Do you know how I can solve this issue?

Upvotes: 1

Views: 81

Answers (1)

Amadan
Amadan

Reputation: 198526

payment_type will be e.g. "AT" - it's the argument you pass into your function, it will never be a Hash.

This rewrite should do what you want:

def amount_for(payment_type, country = nil, currency = nil)
  path = [payment_type, country, currency].compact
  obj = AMOUNT
  obj = obj[path.shift] while Hash === obj && !path.empty?
  return obj || 1
end

Alternately, this is rather similar to the code you wrote:

def amount_for(payment_type, country = nil, currency = nil)
  tmp = AMOUNT.dig(payment_type, country, currency)
  return tmp if tmp
  tmp = AMOUNT.dig(payment_type, country)
  return tmp if tmp
  tmp = AMOUNT.dig(payment_type)
  return tmp if tmp
  return 1
end

Upvotes: 1

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