CODEWITHSUNDEEP
swiftdouble
Vishal Parmar
Vishal Parmar

Reputation: 613

Binary operator '*' cannot be applied to operands of type 'Float' and 'Double'

I am implementing AudioVisualizer and I am trying to calculate time of audio but I am getting below error

Binary operator '*' cannot be applied to operands of type 'Float' and 'Double'

Here is my code:

 var lowPassReslts: Double = 0.0
 var lowPassReslts1: Double = 0.0

 let ALPHA: Float = 1.05
    
 let averagePowerForChannel = pow(10, (0.05 * audioPlayer.averagePower(forChannel: 0)))
 lowPassReslts = ALPHA * averagePowerForChannel + (1.0 - ALPHA) * lowPassReslts //HERE i am getting error which i mention above
    
 let averagePowerForChannel1 = pow(10, (0.05 * audioPlayer.averagePower(forChannel: 1)))
 lowPassReslts1 = ALPHA * averagePowerForChannel1 + (1.0 - ALPHA) * lowPassReslts1 //HERE i am getting error

This above code have converted from Objective-C. This code works perfect in Objective-C but it is not working in Swift. Can anyone please tell me how to solve this error?

Please See Screen Shot

Upvotes: 0

Views: 1908

Answers (5)

Angel F Syrus
Angel F Syrus

Reputation: 2042

Make your parameter type of ALPHA as Double or change your lowPassReslts as Float.

Try the following code:

var lowPassReslts: Double = 0.0
var lowPassReslts1: Double = 0.0

let ALPHA: Double = 1.05

let averagePowerForChannel = pow(10, (0.05 * audioPlayer.averagePower(forChannel: 0)))
lowPassReslts = ALPHA * averagePowerForChannel + (1.0 - ALPHA) * lowPassReslts 

let averagePowerForChannel1 = pow(10, (0.05 * audioPlayer.averagePower(forChannel: 1)))
lowPassReslts1 = ALPHA * averagePowerForChannel1 + (1.0 - ALPHA) * lowPassReslts1

In swift there is no need to declare the variable type. You can directly declare the variable as,

  var lowPassReslts = 0.0
  var lowPassReslts1 = 0.0
  let ALPHA = 1.05

Try any of the above method. Hope it will help you.

Upvotes: 0

Mahendra
Mahendra

Reputation: 8914

Unlike in objective C, you can not do operation on 2-different type of variables (as Swift Language is Type-Safe).

To do any arithmetic calculation the type of both operand must be same.

If you do not specify the type of the variable then swift inferences the type from its value.

For eg.

let a = 10    //Swift consider it -> Int type 
let b = 20.0  //Swift consider it -> Double type 

let result = a * b  //Gives compile time error for the operand type 

let result = Double(a) * b  //No error, as Int is converted to Double

Upvotes: 1

Samir Shaikh
Samir Shaikh

Reputation: 557

You need to make same data type for both like both are double or both are float.

Upvotes: 0

Rubiya Faniband
Rubiya Faniband

Reputation: 370

Pow(Double, Double) it accepts the double and returns the double.

let ALPHA: Float = 1.05, you explicitly declared the Float(change the naming convention, should not be all caps).

in swift, you cannot do any binary operation with two different types.

Solution: change the alpha type to double or don't declare the data type else convert it to double during operation.

Upvotes: 0

Bhavesh Nayi
Bhavesh Nayi

Reputation: 715

    var lowPassReslts: Double = 0.0
    var lowPassReslts1: Double = 0.0

    let ALPHA: Float = 1.05

    let averagePowerForChannel = pow(10, (0.05 * audioPlayer.averagePower(forChannel: 0)))
    lowPassReslts = Double(ALPHA * Float(averagePowerForChannel) + (1.0 - ALPHA) * Float(lowPassReslts))

    let averagePowerForChannel1 = pow(10, (0.05 * audioPlayer.averagePower(forChannel: 1)))
    lowPassReslts1 = Double(ALPHA * Float(averagePowerForChannel1) + (1.0 - ALPHA) * Float(lowPassReslts1))

Upvotes: 1

Related Questions