Reputation:
by wanting to create a musical bot, I quickly noticed by ending coded that the bot does not start for an error that is indicated below the code. Thank you for enlightening me as possible.
Thanks to help me
switch (args[0].tolowerCase()) {
case "play":
if (!args[1]) {
message.channel.send("Indiquez le __lien__ s'il vous plaît !");
return;
}
if(!message.member.voiceChannel) {
message.channel.send("Vous devez vous trouvez dans un salon **vocal**
!");
return;
}
if(!servers[message.guild.id]) servers[message.guild.id] = {
queue : []
}
var server = servers[message.guild.id]
server.queue.push(args[1]);
if(!message.guild.voiceConnection)
message.member.voiceChannel.join().then(function(connection) {
play(connection, message);
})
break;
case "skip" :
var server = servers[message.guild.id];
if (server.dispatcher) server.dispatcher.end();
break;
case "stop" :
var servers = servers[message.guild.id];
if (message.guild.voiceConnection)
message.guild.voiceConnection.disconnect();
break;
default:
message.channel.send("La commande saisie est invalide !");
}
This is the console log.
ReferenceError: args is not defined
at Object.<anonymous> (C:\Users\Thomas\Desktop\Nolosha
Bot\index.js:170:1)
Upvotes: 1
Views: 8708
Reputation: 5623
Welcome to Stack Overflow.
The error you receive is saying that you haven't declared the variable args
, but you're trying to use it anyway. Make sure that you have set args
prior to using it.
const args = message.content.trim().split(/ +/g);
This code takes the message content, removes any whitespace on the beginning or end, and then splits it up into pieces by spaces, returning an array. Keep in mind that it can't be redefined within the same block because it's a constant.
Upvotes: 3