Reputation: 87
I am trying to store the class member of class A as a const reference in class B (which is controlled by A) so that I can modify the value only through class A but B can still read it. The problem is that the address of the class A members change after the constructor finishes so the reference members in class B won't point to the class A members anymore.
Each object A runs in a separate thread. I don't get different addresses when I don't use multithreading so I know that's what's causing the problem but I can't figure out what's going wrong.
#include <thread>
#include <vector>
#include <iostream>
using namespace std;
class B
{
private:
const float& m_foo;
public:
friend class A;
B(const float& foo):
m_foo(foo)
{
cout << "m_b.m_foo address in B constructor:\t" << &m_foo << endl;
}
};
class A {
private:
float m_foo;
B m_b;
public:
A(float foo):
m_foo(foo),
m_b(m_foo)
{
cout << "m_a.m_foo address in A constructor:\t" << &m_foo << endl;
cout << "m_b.m_foo address in A constructor:\t" << &(m_b.m_foo) << endl;
}
void run()
{
cout << "m_a.m_foo address after A and B constructor:\t" << &m_foo << endl;
cout << "m_b.m_foo address after A and B constructor:\t" << &(m_b.m_foo) << endl;
}
};
int main(int argc, char *argv[]){
int n = 1;
vector<A> vector_A;
vector<thread> threads;
vector_A.reserve(n);
for (int i=0; i<n; i++){
// Store A objects inside vector_A
vector_A.push_back(A(10));
// Store the threads inside the threads vector
threads.push_back(thread(&A::run,
std::ref(vector_A[i])));}
for (int i=0; i<n; i++){
// Wait for the rest of the thread to finish
threads[i].join();
}
return 0;
}
Output:
m_b.m_foo address in B constructor: 0x7ffee160d708
m_a.m_foo address in A constructor: 0x7ffee160d708
m_b.m_foo address in A constructor: 0x7ffee160d708
m_a.m_foo address after A and B constructor: 0x7faab8c02af0
m_b.m_foo address after A and B constructor: 0x7ffee160d708
Upvotes: 1
Views: 314
Reputation: 436
You can use something like this: (it works for me)
A
objects and call run
:void newA_run(vector<A>& v, float val){
// Store A objects inside vector_A
A a(val);
v.push_back(a);
a.run();
}
int main(int argc, char *argv[]){
int n = 1;
vector<A> vector_A;
vector<thread> threads;
vector_A.reserve(n);
for (int i=0; i<n; i++){
// Store the threads inside the threads vector
//threads.push_back(thread(&A::run, std::ref(vector_A[i])));}
threads.push_back(thread(&newA_run,
std::ref(vector_A),
10));
}
for (int i=0; i<n; i++){
// Wait for the rest of the thread to finish
threads[i].join();
}
return 0;
}
Update:
There is a easier way:
vector_A
in main
as follows:int main(int argc, char *argv[]){
int n = 1;
A* vector_A[n];// = (A*) malloc(n * sizeof(A));
vector<thread> threads;
for (int i=0; i<n; i++){
// Store A objects inside vector_A
vector_A[i] = new A(10);
// Store the threads inside the threads vector
threads.push_back(thread(&A::run,
std::ref( *vector_A[i] )));}
for (int i=0; i<n; i++){
// Wait for the rest of the thread to finish
threads[i].join();
// I put public 'm_foo' in both classes and 'm_b', to check after join
// and it works fine.
cout << "m_a.m_foo address after join:\t" << &(vector_A[i]->m_foo) << endl;
cout << "m_b.m_foo address after join:\t" << &(vector_A[i]->m_b.m_foo) << endl;
}
return 0;
}
Hope it helps you.
Upvotes: 2