CODEWITHSUNDEEP
python
MrSuspicious
MrSuspicious

Reputation: 3

Output list to variable sized formatted string

I'm trying to write a function that can take a list and turn it into a string where each value is line seperated.

I've tried using string multiplication with formatting

d = ["one", "two", "three"]

dstring = ("{}\n"*(len(d)-1)).format(d)

print(dstring)

My intended result is that a set of braces would be generated per element in the list and could then be formatted with just the list.

So it would return

one
two
three

and any other elements in that format should the list get bigger.

But instead it returns

IndexError: tuple index out of range

Upvotes: 0

Views: 50

Answers (3)

Daniel
Daniel

Reputation: 42748

format needs n parameters, e.g. by using *:

dstring = ("{}\n"*len(d)).format(*d)

Upvotes: 0

Devesh Kumar Singh
Devesh Kumar Singh

Reputation: 20490

Use str.join, which joins items in a list together, with the provided delimiter between them, which in our case is\n

d = ["one", "two", "three"]
res = '\n'.join(d)
print(res)
#one\ntwo\nthree

The output is

one
two
three

Or if you want the list with \n appended at the end of each list, you can use a list-comprehension

d = ["one", "two", "three"]
res = [f'{item}\n' for item in d]
print(res)

The output is 

['one\n', 'two\n', 'three\n']

Upvotes: 1

Aero Blue
Aero Blue

Reputation: 526

I would use a short list comprehension for this:

d = ["one", "two", "three"]

c = [b+"\n" for b in d]

print(c)

Which gives you the desired output:

['one\n', 'two\n', 'three\n']

Upvotes: 0

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