CODEWITHSUNDEEP
javascript
Darren
Darren

Reputation: 2290

Conditional promise in JS

I am trying to reduce the need for multiple functions, especially as many have a promise that is doing the same thing. However, I am looking to add a condition based on props from a parent.

For example I have a function

example
  .doSomething()
  .then(something => {
    example.createSomething(something)
  });

But how can I add a condition that changes .doSomething() from props of somethingElse to .doSomethingElse()?

Therefore, if somethingElse === true the function will be 

example
  .doSomethingElse()
  .then(something => {
    example.createSomething(something)
  });

Upvotes: 1

Views: 623

Answers (2)

ab_qayyum
ab_qayyum

Reputation: 102

You can use Promise.all method

let cleaRoom = function(){
        return new Promise(function(resolve, reject){
            resolve('room is cleaed')
        })
    }
    let removeGarbage = function(message){
        return new Promise(function(resolve, reject){
            resolve(message + ' garbage is removed')
        })
    }
    let wonIcecream = function(message){
        return new Promise(function(resolve, reject){
            resolve(message + ' won the icecream');
        })
    }
Promise.all([cleaRoom(),removeGarbage(),wonIcecream()]).then(function(){
    console.log('finished all');
})

Upvotes: 0

Valen
Valen

Reputation: 1763

I am writing this in my phone don't blame me, might tidy up later.

Promise.resolve(somethingElse ? example.doSomethingElse() : example.doSomething())
    .then(...

if you think writing twice example is tedious

Promise.resolve(example[somethingElse ? "doSomethingElse" : "doSomething"]())
    .then(...

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Promise

By @Phil

if both(all) functions return a Promise can simply do

example[somethingElse ? "doSomethingElse" : "doSomething"]().then(...

Note that it means Promise.resolve above can even handle non-Promise return value

Upvotes: 2

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