Reputation: 59
I am making a program with a graph that scrolls and I just need to move a section of the screen.
If I do something like this:
import pygame
screen = pygame.display.set_mode((300, 300))
sub = screen.subsurface((0,0,20,20))
screen.blit(sub, (30,40))
pygame.display.update()
It gives the error message: pygame.error: Surfaces must not be locked during blit
I assume it means the child is locked to its parent surface or something but how else could I go about doing this?
Upvotes: 1
Views: 564
Reputation: 210968
screen.subsurface
creates a surface, which reference to the original surface. From documentation:
Returns a new Surface that shares its pixels with its new parent.
To avoid undefined behaviour, the surfaces get locked. You've to .copy
the surface, before you can .blit
it to its source:
sub = screen.subsurface((0,0,20,20)).copy()
screen.blit(sub, (30,40))
Upvotes: 2
Reputation: 101072
Just don't draw to the screen surface directly. Create a Surface
for each part of your game/UI, and blit each of those to the screen.
import pygame
def main():
pygame.init()
screen = pygame.display.set_mode((640, 480))
# create two parts: a left part and a right part
left_screen = pygame.Surface((400, 480))
left_screen.fill((100, 0, 0))
right_screen = pygame.Surface((240, 480))
right_screen.fill((200, 200, 0))
x = 100
while True:
events = pygame.event.get()
for e in events:
if e.type == pygame.QUIT:
return
# don't draw to the screen surface directly
# draw stuff either on the left_screen or right_screen
x += 1
left_screen.fill(((x / 10) % 255, 0, 0))
# then just blit both parts to the screen surface
screen.blit(left_screen, (0, 0))
screen.blit(right_screen, (400, 0))
pygame.display.flip()
if __name__ == '__main__':
main()
Upvotes: 1