CODEWITHSUNDEEP
regexperlawksedword-list
bobylapointe
bobylapointe

Reputation: 683

Remove lines with more than x digits

I'd like to find a way to delete lines containing more than 4 digits using awk or sed:

input:

test12test1
test154test43test
test12

desired output:

test12test1
test12

How do I solve this problem?

Upvotes: -3

Views: 360

Answers (3)

Jotne
Jotne

Reputation: 41456

One of these may do.

awk -F '[0-9]' 'NF<=5' file
test12test1
test12

awk -F '[0-9]' 'NF<6' file
test12test1
test12

Set the field separator to any possible decimal digit and then perform a test on the total number of fields.
Since you get a field before and after the field-separator, you need to test if the line more than 5 fields to determine if the line has more than 4 decimals.

Upvotes: 5

potong
potong

Reputation: 58400

This might work for you (GNU sed):

sed 's/[0-9]/&/4;T;d' file

If one can replace the 4th digit, then delete the line.

Upvotes: 1

glenn jackman
glenn jackman

Reputation: 246807

The perl tr/// operator returns the number of substitutions, so 

perl -ne 'print if tr/0-9/0-9/ <= 4' file

Or if you want to use a shell variable

max_digits=4
perl -sne 'print unless tr/0-9/0-9/ > $max' -- -max=$max_digits file

Upvotes: 3

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