CODEWITHSUNDEEP
c++cdebugginglldb
felipecrv
felipecrv

Reputation: 2021

How to step-into outermost function call in the line with LLDB?

Let's say I'm debugging code like this

   outer(fn1(), fn2());

If I use the s command, LLDB will first step into fn1, then I type fin to step-out, s again steps into fn2, fin... and only now I'm able to step-into outer which is what I wanted since the beginning.

Is there a way to tell LLDB on which function call to step-in?

Upvotes: 5

Views: 1427

Answers (3)

Dave Lee
Dave Lee

Reputation: 6489

lldb comes with an alias for exactly this: sif. In the given example, you can run:

(lldb) sif outer

You can remember it as step into function

It works with partial matches, it doesn't have to be called with the full function name. In this case, you could also run sif out for example.

Upvotes: 6

Jason Molenda
Jason Molenda

Reputation: 15395

thread step-in --step-in-target outer or more compactly, s -t outer will stop when it has stepped into outer. See help s for the documentation.

Upvotes: 2

Deepak Agarwal
Deepak Agarwal

Reputation: 1

Directly No. But you can set a break point in definition of outer function.

Upvotes: -3

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