CODEWITHSUNDEEP
python
Gromit
Gromit

Reputation: 63

Remove random text from filename based on list

So I have a list of files from glob that are formated in the following way

filename xx xxx moretxt.txt

what I'am trying to do is rename them as follows

filename.txt

the first two xx is one of these:

[1B, 2B, 3B, 4B, 5B, 6B, 7B, 8B, 9B, 10B, 11B, 12B, 1A, 2A, 3A, 4A, 5A, 6A, 7A, 8A, 9A, 10A, 11A, 12A]

so how do I remove the "xx xxx moretxt" from the file name and keep the extension?

import glob, os
os.chdir("C:\\somepath")

for file in glob.glob("**/*.txt", recursive = True):
    print(file)

Upvotes: 2

Views: 225

Answers (2)

Gromit
Gromit

Reputation: 63

When I try this, I only get one filename..

import re  
import glob, os  
os.chdir("C:\\Somepath")  

for filename in glob.glob("**/*.txt", recursive = True):  
    filename = re.match(r"(?P<filename>\w+).*\.(?P<ext>.+)", filename)  
    filename = "{}.{}".format(filename.group('filename'), filename.group('ext'))  
    print(filename)

output:
screw12323.txt
screw12323.txt
screw12323.txt
screw12323.txt
screw12323.txt '

Upvotes: 0

Rakesh
Rakesh

Reputation: 82815

Using str.split

Ex:

filename = "filename xx xxx moretxt.txt"
val = filename.split()
filename = "{}.{}".format(val[0], val[-1].split(".")[-1])
print(filename)

or using re.match

Ex:

import re

filename = "filename xx xxx moretxt.txt"

filename = re.match(r"(?P<filename>\w+).*\.(?P<ext>.+)", filename)
filename = "{}.{}".format(filename.group('filename'), filename.group('ext'))
print(filename)

Output:

filename.txt

Upvotes: 2

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