CODEWITHSUNDEEP
python
galelamanzi
galelamanzi

Reputation: 3

Initialize class instance in a loop over a list

I have a class where I assign a rating to each instance. 

class Team:

def __init__(self, rating):
    "Initialize team with rating"
    self.rating = rating

I would like to be able to loop over a list of ratings, and create an instance for each rating, so if I have a list of ratings and team names, something like this:

scores = [10, 11, 12, 13]
teams = ['tm0', 'tm1', 'tm2', 'tm3']

for t, s in zip(teams, scores):
    t = Team(s)

tm2.rating    # returns 12

The above is not defining an instance of Team like I want it to.

I am new to Python so suspect there is an easy fix, or a more Pythonic way of doing this.

Upvotes: 0

Views: 68

Answers (2)

chepner
chepner

Reputation: 530872

You appear to want a dict that maps each team name to an instance of Team.

scores = [10, 11, 12, 13]
team_names = ['tm0', 'tm1', 'tm2', 'tm3']
teams = {t: Team(s) for t, s in zip(team_names, scores)}

assert teams['tm0'].rating == 10

Upvotes: 3

PirateNinjas
PirateNinjas

Reputation: 2076

You can achieve what you want here with exec:

for t,s in zip(teams, scores):
    exec(f"{t} = Team({s})")

Upvotes: 0

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