Reputation: 29

Write a method to print out a string "Name" multiple times

I am answering a question for an Intro to Programming class and cannot - after reading through my notes, Big Java book, and looking online - find out where to begin.

It seems as though it should be very simple, but I just need to get started. All of this is for Java and is being worked on in Eclipse.

The task is to take in a name ("Name") and a number (int x) and display the "Name" x number of times on one line, x-1 times on another line, and so on and so on until you display the name only once. It seems like it should be a reverse accumulator, but I'm having trouble starting my method. How do I begin? I know I can't multiply strings in Java like you can in python or other languages, but how can I print the "Name" x number of times without building an Array or inputing

System.out.println("name" + " " + "name" + " "...).

Any suggestions are appreciated. I am a novice at this. Thank you!

Upvotes: 2

Answers (10)

Niranjan Kumar

Reputation: 1

public class WithoutLoop
{
      static int count;
   public static void repeat(String s)
   {
       while(count <= 10)
       {
           System.out.println(s);
           count++;
       }
   }
   public static void main(String[] args)
   {
        repeat("hello");
   }
}

Upvotes: 0

joe BG

Reputation: 1

int x;
int y = 1;

x = scanner.nextInt();

for (int i = 1; i <= x; i++) {
    for (int j = 1; j <= y; j++) {
        System.out.print("O");
    }
    System.out.println();
    ++y;
}

Upvotes: 0

Marc Arial

Reputation: 1

public class test{

    public static void main(String[] args){

        int i = 0;
        int j = 20;

   for(i = 1; i <= j; i++){

          System.out.println("My Name");


   } //ends for loop

     // use system.out.print("") for same line 


}    //ends static void main

}

Upvotes: 0

Mahendra Liya

Reputation: 13218

You can do this by using System.out.print and System.out.println.

Here is the sample code: (not the actual code which you want, just a SAMPLE)

import java.io.*;

public class StringNameTest
{
    public static void main(String args[])
    {
            String strNumber = "";
            String strName = "";
            int intNumber;
            try 
            {
                //  open up standard input
                BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

                //  prompt the user to enter their name
                System.out.print("Enter your name: ");
                strName = br.readLine();

                System.out.print("Enter the number of times you want to print your name: ");
                strNumber = br.readLine();
                intNumber = Integer.parse(strNumber);

                for (row = 0; row < intNumber; row++)
                {
                    for(col = 0; col < intNumber; col++)
                        System.out.print(strName + " ");

                    System.out.println("");
                }
            } 
            catch (Exception ex) {
                System.out.println(ex.getMessage());
                System.exit(1);
            }


    }
}

Hope this helps.

Upvotes: 1

Martijn Courteaux

Reputation: 68847

First thought: you need n lines. So, enter a loop.

for (int i = 0; i < n; ++i)
{

Then: you need to print on line i the string n - i times. Enter a nested loop:

     for (int j = 0; j < n - i; ++j)
     {

Then start off printing the name:

           System.out.print(name + " ");
     }

Notice I didn't use println, because we want all the names on the same line.
Now you need to end the line when we printed n - i times:

     System.out.println();

Close our outer-loop:

And if you don't know how to make the program ask the name and the integer n to the user:

String name = null;
int n = 0;
try
{
    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    System.out.print("Enter the name: ");
    name = br.readLine();
    System.out.print("How many times (n): ");
    n = Integer.parseInt(br.readLine());
} catch (Exception e)
{
    e.printStackTrace();
    System.exit(-1); // exit!, there was an error
}

Upvotes: 0

Roland Illig

Reputation: 41627

It is correct that Java doesn't have built-in String repetition. But you can define your own method that does exactly this.

public static String repeated(String s, int times) {
  StringBuilder sb = new StringBuilder();
  // TODO: append /s/ to /sb/ for /times/ times.
  return sb.toString();
}

Good point for you that you want to use this "operator" instead of putting together everything into one large block of code. This helps to keep your programs readable.

Upvotes: 0

Ekkehard.Horner

Reputation: 38745

Use an outer loop that counts to x and an inner loop that counts to (x - outer loop counter). Be aware of the common "one off" error.

Upvotes: 0

rsp

Reputation: 23373

Your method gets a string with the name and a count. Using one for loop to count and another to repeat the name value, you should be able to get the output you're after.

System.out is a printstream and it has both println() to output a line ended with a linebreak and print() to output a string without ending it with a linebreak.

Upvotes: 1