CODEWITHSUNDEEP
python
pythonTron1
pythonTron1

Reputation: 11

How to keep track of various types of streaks

I am writing a script that watches an online coin flip game, and keeps a tally of the results. I would like to find a simpler way of finding out how many times the streak ended after three of the same results, four of the same result etc.

if result = heads:
headsCount += 1
headsStreak +=1

tailsCount = 0
tailsStreak = 0

headsCount is the total amount of heads results witnessed in a session, and the streak is just so I can display how many heads have appeared in a row. This is update by:

if headsCount >= headsStreak:
headsStreak = headsCount

My problem - I wish to keep track of how many times the streak ends at one, ends at two, ends at three etc...

A silly way I have for now:

if headsStreak = 1:
    oneHeadsStreak +=1
if headsStreak = 2
    twoHeadsStreal +=1

But it is very tedious. So is there an easier way to create the variables... for example:

for i in range (1, 20):
    (i)streak = 0

and then something like

for i in range (1, 20):
    if headsStreak = i:
        (i)streak += 1

Thank you in advance!

Upvotes: 1

Views: 262

Answers (2)

Sayse
Sayse

Reputation: 43320

Using a defaultdict, You just need three variables,

from collections import defaultdict
current_streak = 0
current_side = "heads"
streak_changes = defaultdict(int)

Then store the values in a dictionary when the streak changes

if side == current_side:
    current_streak += 1
else:
    current_side = side
    streak_changes[current_streak] += 1
    current_streak = 1

Upvotes: 0

Olaf
Olaf

Reputation: 606

You could use a list to keep track of the streak counter. You will have to think about which index is which streak length (e.g. index 0 is for streak length 1, index 1 for length 2 etc.).

Initialize all list elements to zero: l = [0 for i in range(20)] Then, whenever a streak ends, increment the list element at the corresponding index: l[3] += 1 for a 4-streak.

Upvotes: 1

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