Reputation: 507
I have two JSON files.
file1.json:
{
"Fruits": [
{
"name": "Apple",
"something_else": 123,
"id": 652090
},
{
"name": "Orange",
"something_else": 456,
"id": 28748
}
]}
file2.json:
{
"Fruits": [
{
"weight": 5,
"id": 652090
},
{
"weight": 7,
"id": 28748
}
]}
I want to combine objects from both files if they have a common key 'id', but to extract only 'name' property from file1. How do I do that using jq?
This is what I want to get:
{
"Fruits": [
{
"name": "Apple",
"weight": 5,
"id": 652090
},
{
"name": "Orange",
"weight": 7,
"id": 28748
},
]}
Upvotes: 0
Views: 436
Reputation: 134571
There's plenty of ways this could be constructed. Here's another way:
$ jq '.Fruits |= (. + input.Fruits | [group_by(.id)[] | add | {name,weight,id}])' \
file1.json file2.json
{
"Fruits": [
{
"name": "Orange",
"weight": 7,
"id": 28748
},
{
"name": "Apple",
"weight": 5,
"id": 652090
}
]
}
Upvotes: 1
Reputation: 50795
Combine Fruits
arrays, group it by id
, select groups with 2 elements because we want fruits present in both files. For each selected group; add name
field from first group element to second, and collect results in an array.
jq -n '[inputs.Fruits[]]
| reduce (group_by(.id)[] | select(length==2)) as $f
([]; . + [$f[1] + ($f[0] | {name})])' file1.json file2.json
Note that the order files are given on the command line is important, the file with name
s should be given before the other.
Combining objects with same id
and extracting a subset of fields is way much easier though:
jq -n '[inputs.Fruits[]]
| group_by(.id)
| map(select(length==2) | add | {name, id, weight})
' file1.json file2.json
Upvotes: 1