Reputation: 4042
The method is
public Set<BluetoothDevice> getBondedDevices ()
from Android.bluetooth.BluetoothAdapter.
I read the type signature guidance here, including how to specify an object with Lclass-name; but I don't know how to extend that to a generic class (or even if it is possible).
Upvotes: 0
Views: 155
Reputation: 13405
If you are not sure what is the signature of the method, javap
comes to rescue.
import java.util.*;
public class Example {
public Set<Float> getSet() {
return null;
}
}
you can easily check the signature following way
> javac Example.java
> javap -s -cp . Example
Compiled from "Example.java"
public class Example {
public Example();
descriptor: ()V
public java.util.Set<java.lang.Float> getSet();
descriptor: ()Ljava/util/Set;
}
Upvotes: 1
Reputation: 2824
You are asking about Type Erasure in java. Your answer is Object. If you have:
List<E> myList;
The compiler will interpret E as Object. This case is known as Class Type Erasure. There is also a case called Method Type Erasure.
Upvotes: 0
Reputation: 887867
Generics do not exist at runtime; AFAIK, that syntax does not support type parameters.
I'm not sure if that applies to type parameters for base classes (which do exist at runtime in Reflection).
Upvotes: 1