CODEWITHSUNDEEP
python
goose goose
goose goose

Reputation: 96

Variable is undefined error. Calling a variable outside of condition in python

I'm parsing xml data and when i print the variable inside the condition but when i call that same variable later is not defined. Why does this happen

Here the variable "LaunchPath works fine:

import xml.sax

class PathHandler( xml.sax.ContentHandler ):
   def __init__(self):
      self.CurrentData = ""

   # Call when an element starts
   def startElement(self, tag, attributes):
      self.CurrentData = tag
      if tag == "application":
         LaunchApp = attributes["android:name"].replace(".", "/")
         LaunchPath = LaunchApp + ".smali"
         print LaunchPath

if ( __name__ == "__main__"):

   # create an XMLReader
   parser = xml.sax.make_parser()
   # turn off namepsaces
   parser.setFeature(xml.sax.handler.feature_namespaces, 0)

   # override the default ContextHandler
   Handler = PathHandler()
   parser.setContentHandler( Handler )

   parser.parse("AndroidManifest.xml")

But when i attempt to print "LaunchPath" at the bottom like this it doesn work:

import xml.sax

class PathHandler( xml.sax.ContentHandler ):
   def __init__(self):
      self.CurrentData = ""

   # Call when an element starts
   def startElement(self, tag, attributes):
      self.CurrentData = tag
      if tag == "application":
         LaunchApp = attributes["android:name"].replace(".", "/")
         LaunchPath = LaunchApp + ".smali"

if ( __name__ == "__main__"):

   # create an XMLReader
   parser = xml.sax.make_parser()
   # turn off namepsaces
   parser.setFeature(xml.sax.handler.feature_namespaces, 0)

   # override the default ContextHandler
   Handler = PathHandler()
   parser.setContentHandler( Handler )

   parser.parse("AndroidManifest.xml")

print LaunchPath

This gives me an error that "LaunchPath" is undefined.

Why does this happen and how can i fix it.

Upvotes: 0

Views: 44

Answers (2)

Will
Will

Reputation: 1169

That is because LaunchPath is a local variable and you are trying to reference it out of its scope.

Upvotes: 0

Vitor Falcão
Vitor Falcão

Reputation: 1049

This is because your variable LaunchPath is defined inside the scope of the function startElement, since you declared it there when the functions returns it also "erases" the variable.

You should read about python scopes

Upvotes: 3

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