CODEWITHSUNDEEP
cbash
José Ca
José Ca

Reputation: 19

How to write a script to run a program multiple times and store the time in a file?

I am trying to run a script to run my program written in C that is just a simple sorting program to compare it to the built in function in unix. I want to take the user time from both sort (unix) and my sort function 100 times and put it in a file excel, csv to compare the algorithms.

Both my function and the sort function work when I run it manually but I dont know how to write code to automate this process for 100 times.

#!/bin/sh
for i in {1..100}
do
     for t in 01
     do
     echo ===Test $t ====
     time sort -n <tests/$t > tests/$t.expected
     time ./useIntList <tests/$t> tests/$t.observed
     done
done
rm tests/*.expected tests/*.obsereved

I get the program run 100 times but I dont know how to get the user time into an array and print it into a file.

Upvotes: 2

Views: 2341

Answers (1)

Barmar
Barmar

Reputation: 780714

time writes its output to stderr, not stdout. It's also a shell built-in that executes the command after it, including the I/O redirections, outside the timing. So you need to put the time command in a block, and redirect outside the block.

You should also use #!/bin/bash. Syntax like {1..100} is a bash extension, it might not be available when you use #!/bin/sh.

#!/bin/sh
for i in {1..100}
do
     for t in 01
     do
     echo ===Test $t ====
     { time sort -n <tests/$t > tests/$t.expected; } 2>tests/$t.time.expected
     { time ./useIntList <tests/$t> tests/$t.observed; } 2>tests/$t.time.observed
     done
done
rm tests/*.expected tests/*.obsereved

The *.time.* files will contain the output of time.

Upvotes: 3

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