CODEWITHSUNDEEP
c++mutators
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Reputation: 55

Why is member function call "ambiguous"?

Why is my overloaded member function only "ambiguous" as a char and not an int and string?

I'm trying to create a one-code path for my Char class by funneling code through an overloaded equals() function. It works fine when I use equals as an int and string but is ambiguous as a char.

class Char
{
private:
    char cData;
    int iData;
    string sData;
public:
    //Mutators:
    void equals(char c);
    void equals(int c);
    void equals(string c);

    //Constructors:
    Char(char c);
    Char(int c);
    Char(string c);
};

void Char::equals(char c)
{
    cData = c;
}

void Char::equals(int c)
{
    iData = c;
}

void Char::equals(string c)
{
    sData = c;
}

Char::Char(char c)
{
    this->equals(c); //Call to member function 'equals' is ambiguous
}

Char::Char(int c)
{
    this->equals(c);
}

Char::Char(string c)
{
    this->equals(c);
}

The error only happens for char, which is confusing since string works fine. I expected it to work for all of them since that's been the case so far.

Upvotes: 0

Views: 1127

Answers (2)

d3v-sci
d3v-sci

Reputation: 173

you can use a single equal method to accept a char or an int. like

void euqals(unsigned int c_i);

Upvotes: 0

Jesper Juhl
Jesper Juhl

Reputation: 31459

It's ambiguous because if you do

Char c(42);

The compiler does not know whether it should call the char or int constructor. Both are an equally good match.

The same goes for equals(123);. Again, both the char and int overloads match and the compiler cannot tell which one you intend to call.

Upvotes: 1

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