Reputation: 6997
Am trying to query from parent to child and with a single query being able to have the child results in parent. In my example, am trying to do a relation between i18n tables in which I want to include the row from the child table in a single hit.
models.py
class main(models.Model):
slug = models.SlugField()
is_active = models.BooleanField(default=True)
site = models.ForeignKey(Site)
def __unicode__(self):
return self.slug
class main_i18n(models.Model):
main = models.ForeignKey(main)
language = models.CharField(max_length=2, choices=LANGUAGES)
title = models.CharField(max_length=50)
class Meta:
unique_together = (("language", "main"))
def __unicode__(self):
return self.title
I tried the following to query
a=main.objects.filter(is_active=True, main_i18n__language='en')
and the relation its done perfectly, here is what I saw when tried to print the query
>>> a.query.__str__()
'SELECT `category_main`.`id`, `category_main`.`slug`, `category_main`.`is_active`, `category_main`.`site_id` FROM `category_main` INNER JOIN `category_main_i18n` ON (`category_main`.`id` = `category_main_i18n`.`main_id`) WHERE (`category_main_i18n`.`language` = en AND `category_main`.`is_active` = True )'
As you see from the query, it does the join correctly but the column names is not included in the select statement. I cannot access the main_i18n data when trying to do a for loop.
sorry for my lousy english and hope i can find help,
Best wishes,
---- EDIT:
below is the template am currently using, ultimately I would really like to create a single query and do regrouping based to list the data in my view.
<table class="homepage-listing">
<tr>
<td>
{# {% regroup list by main as rg_main %}#}
{% for obj in main %}
{# {% if obj.grouper != None %}#}
<div class="listing-block">
<a href="#" ><h3>{{ obj }}</h3></a>
<ul>
{% for s in obj.list %}
<li>{{ s.list_i18n_set.get }} </li>
{% endfor %}
</ul>
</div>
{# {% endif %}#}
{% endfor %}
</td>
</tr>
</table>
--- EDIT:
I had to use the extra functions to to build a single query for that purpose. I started with it but getting a bit complicated, am trying to make sure the columns not hardcoded in the queries and the joins are correct. Can anyone tell me if there is a better way to write the query?
dict = Main.objects.extra(
select=
{
'main_title' : '%s.%s' % (MainI18n._meta.db_table, MainI18n._meta.get_field('title').verbose_name),
'list_title' : '%s.%s' % (ListI18n._meta.db_table, ListI18n._meta.get_field('title').verbose_name),
},
tables=[
'%s' % (MainI18n._meta.db_table),
'%s' % (List._meta.db_table),
'%s' % (ListI18n._meta.db_table),
],
where=[
'%s.%s=%s.%s' % (MainI18n._meta.db_table, 'main_id', Main._meta.db_table, 'id'),
'%s.main_id=%s.id' % (List._meta.db_table, Main._meta.db_table),
'%s.list_id=%s.id' % (ListI18n._meta.db_table, List._meta.db_table),
'category_listi18n.language="%s"' % (request.LANGUAGE_CODE)
]).select_related().filter(maini18n__language=request.LANGUAGE_CODE )
Upvotes: 2
Views: 1959
Reputation: 3461
You could query MainI18N
instead:
MainI18N.objects.filter(main__is_active=True, language='en').select_related('main')
EDIT: You can wrap this in a custom queryset method. The quick solution (which doesn't allow you to further filter the QuerySet) would look something like this:
class MainQuerySet(QuerySet):
def translate(self, lang):
for obj in MainI18N.filter(language=lang, main__in=self).select_related('main'):
main = obj.main
main.i18n = obj
yield main
Upvotes: 1
Reputation: 2822
When you use a foreign key you need to access that data through the RelatedManager. In your case you would access data in the main_i18n from the main like:
>>> a=main.objects.get(id=1)
>>> i18n = a.main_i18n_set.get()
>>> i18n.language
u'en'
or if you need to operate on multiple objects:
a = main.objects.filter(is_active=True, main_i18n__language='en')
for obj in a:
i18n = obj.main_i18n_set.get()
print i18n.language
which would of course print 'en' for each object return by the filter.
Upvotes: 2