Reputation: 4481
df1 <- data.frame(
" " = c(" ", "Part Number 1", "Part Number 2", "Part Number 3"),
Julie = c("Measurement 1", 33, 34, 33),
Julie = c("Measurement 2", 32, 31, 31),
Joe = c("Measurement 1", 33, 33, 30),
Joe = c("Measurement 2", 31, 32, 31))
df1 %>%
mutate_all(as.character) %>%
set_names(c("Part", paste(names(.)[2:ncol(.)], .[1, 2:ncol(.)], sep = "-"))) %>%
`[`(2:nrow(.), ) %>%
gather("key", "value", contains("Measurement")) %>%
separate("key", c("person", "measurement"), sep = "-") %>%
mutate_at("person", ~ stringr::str_replace(.x, "\\..*","")) # line 14
# mutate_at("person", ~ stringr::str_replace(., "\\..*","")) # line 15
There's only one thing I want to highlight in the code above, and that's the difference between line #14 and line #15. Notice that the str_replace()
piped data set for line #14 is .x
and the piped data set for line #15 is just .
. I'm used to seeing things in the form of line #15, and it seems the x
in line #14 is benign.
But the x
is not benign. If I include it in similar mtcars code (below) I get an error instead of a 'TRUE'. Can you explain this? I've never seen this mysterious x
syntax before, which hardly means it's not important (or common).
identical(mtcars %>% .[1:2, ],
mtcars %>% .x[1:2, ])
# Error in `[.data.frame`(., .x, 1:2, ) : object '.x' not found
Upvotes: 5
Views: 2426
Reputation: 206197
The .
is the basic unit of transfer for the magrittr
pipelines (which dplyr
imports). It contains the value coming from the pipe.
The .x
value is something that the tidyverse world added. It's used then you have anonymous functions created with the ~
(tilde) syntax. This calls rlang::as_function
to turn that formula into a function. It's basically a short cut so rather than having to type out function(x) x+5
, you can just write ~.x+5
. Since functions can have more than one parameter, it can be helpful to use names for that parameter so .x
refers to the first parameter (and .y
the second). The as_function
also allows you to use .
as an alias for the first parameter. It can do this because the ~
creates a formula and magrittr
doesn't generally replaces .
in formulas so the mapper is free to re-interpret the .
. You can see the function signature here
f <- rlang::as_function(~.x+5)
f
# <lambda>
# function (..., .x = ..1, .y = ..2, . = ..1)
# .x + 5
# attr(,"class")
# [1] "rlang_lambda_function"
You can see how both .
and .x
are alias for ..1
which is the first parameter passed to the function.
Upvotes: 10