CODEWITHSUNDEEP
javaarraysmethods
skelter1987
skelter1987

Reputation: 9

Why can't I call a method with an array variable?

I am trying to print out a simple code but I do not seem to be able to pass the array variable of the method. Sorry if it is something obvious, I am only starting with Java. I am getting the "The method asd in the type MyClass is not applicable for the arguments (int,int,int,int)

public int asd(int[] nums) {
      int count = 0;
      // Note: iterate to length-1, so can use i+1 in the loop
      for (int i=0; i < (nums.length-1); i++) {
        if (nums[i] == 6) {
          if (nums[i+1] == 6 || nums[i+1] == 7) {
            count++;
          }
        }
      }
      return count;
    }

public static void main(String[] args) {
    // TODO Auto-generated method stub

    System.out.println(asd(1,22,3,4,2,2,2));

}

Upvotes: 0

Views: 513

Answers (2)

subhashis
subhashis

Reputation: 4878

you can try this

public static void main(String[] args) {
    int []arr={1,22,3,4,2,2,2}; //this is array literal
    System.out.println(asd(arr));
}

The above program will give compilation error attaching screenshot below

enter image description here

Upvotes: -1

user10316640
user10316640

Reputation:

The method asd is expecting a single parameter of type int []. You are attempting to pass each integer as a separate parameter (resulting in seven parameters , 1,22,3,4,2,2,2).

To correct the compiler-error you can enclose the parameter values in {} and prefix it with new int[] to create an Array literal:

 System.out.println(asd(new int[] {1,22,3,4,2,2,2}));

Upvotes: 5

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