Reputation: 866
I have data with two (potentially more) columns of identifiers (typically long strings). These differ sometimes, are mistyped, or change over time. I want to identify unique subjects in the data. This requires identifying groups of cases which are connected via their ids at some level.
An example
df <- data.frame(ida = c("A", "B", "C", "C", "D", "E"),
idb = c(1, 1, 3, 4, 4, 7),
trueid = c("id1", "id1", "id2", "id2", "id2", "id3"))
> df
ida idb trueid
1 A 1 id1
2 B 1 id1
3 C 3 id2
4 C 4 id2
5 D 4 id2
6 E 7 id3
Identifiers for id1
are "A", "B", 1
, for id2
"C", "D", 3, 4
and for id3
"E", 7
.
I don't know trueid
but need to find it using the information from columns ida
and idb
.
The solution needs to scale to millions of observations with tens of thousands of unique ids. I am already using data.table
.
Extension: There is another scenario where there are more than two columns, and some columns might be informative for others, i.e. have the same identifiers. I do not know which columns are informative for which. I think type can be disregarded though, all columns are strings or can safely be converted.
Another example for this:
df <- data.frame(ida = c("A", "B", "C", "C", "D", "E"),
idb = c("1", "2", "3", "4", "4", "7"),
idc = c("1", "1", "2", "3", "4", "5"),
idd = c("1", "A", "2", "3", "4", "5"),
trueid = c("id1", "id1", "id1", "id1", "id1", "id2"))
> df
ida idb idc idd trueid
1 A 1 1 1 id1
2 B 2 1 A id1
3 C 3 2 2 id1
4 C 4 3 3 id1
5 D 4 4 4 id1
6 E 7 5 5 id2
Edit: As a commenter pointed out, this is essentially the clique problem of finding complete subgraphs in a graph. After reading a bit more, I understand this issue can be solved with library(igraph)
. I am leaving the question open as I would prefer a solution that relies on base
, data.table
or dplyr
. I cannot easily install packages on the server I am using, installing igraph
involves dealing with a lot of red tape and delays.
Edit2: For anybody reading this and facing a similar problem: zx8754
's answer using igraph is considerably (several orders of magnitude) faster on larger (simulated) data with more groups. If you have the chance to use igraph
, do so.
Upvotes: 1
Views: 151
Reputation: 56199
Using igraph:
# example input, I removed "trueid" column
df <- data.frame(ida = c("A", "B", "C", "C", "D", "E"),
idb = c("1", "2", "3", "4", "4", "7"),
idc = c("1", "1", "2", "3", "4", "5"),
idd = c("1", "A", "2", "3", "4", "5"))
#trueid = c("id1", "id1", "id1", "id1", "id1", "id2")
library(igraph)
# set up connections
# Improved version suggested by @thelatemail in the comments
x <- cbind(df[ 1 ], unlist(df[ -1 ]))
# original clumsy version (do not use)
# x <- unique(do.call(rbind, lapply(1:(ncol(df) - 1), function(i) setNames(df[, c(i, i + 1) ], c("from", "to")))))
# convert to graph object
g <- graph_from_data_frame(x)
# plot if you wish to visualise
plot(g)
# this is the solution, add membership ids to original input dataframe
merge(df, data.frame(grp = clusters(g)$membership),
by.x = "ida", by.y = 0)
# ida idb idc idd grp
# 1 A 1 1 1 1
# 2 B 2 1 A 1
# 3 C 3 2 2 1
# 4 C 4 3 3 1
# 5 D 4 4 4 1
# 6 E 7 5 5 2
Upvotes: 4
Reputation: 25225
Here is a recursive approach using data.table
:
#convert into a long format for easier processing
mDT <- melt(DT[, rn := .I], id.var="rn", variable.name="V", value.name="ID")[,
tid := NA_integer_]
#the recursive function
link <- function(ids, label) {
#identify the rows in DT containing ids and extract the IDs
newids <- mDT[mDT[.(ID=ids), on=.(ID), .(rn=rn)], on=.(rn), allow.cartesian=TRUE,
unique(ID)]
#update those rows to the same group
mDT[mDT[.(ID=ids), on=.(ID), .(rn=rn)], on=.(rn), tid := label]
if (length(setdiff(newids, ids)) > 0L) {
#call the recursive function if there are new ids
link(newids, label)
}
}
#get the first id that is not labelled yet
id <- mDT[is.na(tid), ID[1L]]
grp <- 1L
while(!is.na(id)) {
#use recursive function to link them up
link(id, grp)
#repeat for next id that is not part of any group yet
id <- mDT[is.na(tid), ID[1L]]
grp <- grp + 1L
}
#update original DT with tid
DT[mDT, on=.(rn), tid := tid]
data:
library(data.table)
DT <- data.table(ida = c("A", "B", "C", "C", "D", "E"),
idb = c("1", "2", "3", "4", "4", "7"),
idc = c("1", "1", "2", "3", "4", "5"),
idd = c("1", "A", "2", "3", "4", "5"))
Upvotes: 1