CODEWITHSUNDEEP
rstringrstringi
Steve Powell
Steve Powell

Reputation: 1698

replace parts of a string with a vector

I am having problems with replacing parts of a single string with a set of vector replacements, to result in a vector.

I have a string tex which is intended to tell a diagram what text to put as the node (and other) labels.

So if tex is "!label has frequency of !frequency" and T has columns label with values c("chickens","ducks",...) and frequency with values c("chickens","ducks",...) amongst others, the function returns a vector like c("Chickens has frequency of 35","Ducks has frequency of 12",...)

More formally, the problem is:

Given a tibble T and a string tex, return a vector with length nrow(T), of which each element = tex but in which each occurrence within tex of the pattern !pattern is replaced by the vectorised contents of T$pattern

I looked at Replace string in R with patterns and replacements both vectors and String replacement with multiple string but they don't fit my usecase. stringr::str_replace() doesn't do it either.

Upvotes: 0

Views: 159

Answers (1)

Wimpel
Wimpel

Reputation: 27732

possible baseR-solution using sprintf()

animals = c("chickens","ducks") 
frequency = c(35,12)

sprintf( "%s has frequency of %s", animals, frequency)

[1] "chickens has frequency of 35" "ducks has frequency of 12"

also, 

tex = "%s has frequency of %s"
sprintf( tex, animals, frequency )

will gave the same results.

Upvotes: 1

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