CODEWITHSUNDEEP
reactjstypescriptreact-hooks
dorriz
dorriz

Reputation: 2679

Typescript and hooks

Could anyone advise me on the best way to convert this hook to a type safe version using Typescript please. Its a simple toggle to display a different 'thing' on toggle state.

useToggle.js

const useToggleButton = ({on,off}) => {
  const [toggle, setToggle] = React.useState(false)

  const ToggleButton = () => (
    <div
      role="button"
      onClick={() => setToggle(!toggle)}
      data-testid="portal-toggle-btn"
    >
      {toggle? on : off}
    </div>
  )
  return [ToggleButton, toggle, setToggle]
}

The thing is that it returns an array with the component, state and setState function. My attempt is below but I get the errors 

TS2605: JSX element type 'IReturnType' is not a constructor function for JSX elements.   Type 'IReturnType' is missing the
following properties from type 'Element': type, props, key

TS2739: Type '(boolean | Dispatch<SetStateAction<boolean>>)[]' is
missing the following properties from type 'IReturnType': component,
state, func

useToggle.tsx

import * as React from 'react'

interface IToggleBntProps {
  on: any
  off: any
}

interface IState {
  bol: boolean
}

interface IReturnType {
  component: React.FunctionComponent
  state: boolean
  func: (bol: boolean) => IState
}

const useToggleButton = ({ on, off }: IToggleBntProps): IReturnType => {
  const [toggle, setToggle] = React.useState(false)

  const ToggleButton = () => (
    <div
      role="button"
      onClick={() => setToggle(!toggle)}
      data-testid="portal-toggle-btn"
    >
      {toggle ? on : off}
    </div>
  )
  return [ToggleButton, toggle, setToggle]
}

export default useToggleButton

Upvotes: 7

Views: 11431

Answers (1)

JKillian
JKillian

Reputation: 18331

TypeScript can actually figure out most of these types automatically!

In the code below, saying as const (a const assertion) at the end of your return statement lets TypeScript correctly infer the return type you want: [() => JSX.Element, boolean, React.Dispatch<React.SetStateAction<boolean>>].

If you wanted to be explicit, you could do type IReturnType = [() => JSX.Element, boolean, React.Dispatch<React.SetStateAction<boolean>>], but that's verbose and unnecessary.

interface IToggleBntProps {
  on: any
  off: any
}

const useToggleButton = ({ on, off }: IToggleBntProps) => {
  const [toggle, setToggle] = React.useState(false)

  const ToggleButton = () => (
    <div
      role="button"
      onClick={() => setToggle(!toggle)}
      data-testid="portal-toggle-btn"
    >
      {toggle ? on : off}
    </div>
  )

  // saying 'as const' here means that TypeScript automatically
  // knows that this should be a tuple type of three elements.
  // Not you need TypeScript 3.4 or newer 
  return [ToggleButton, toggle, setToggle] as const;
}

export default useToggleButton

Upvotes: 6

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