CODEWITHSUNDEEP
scalaplayframework
DidUMeanRecursion
DidUMeanRecursion

Reputation: 57

How To iterate List[Result] and return one Boolean/Result?

I have a Future[List[Result]] I need to run a logic for example if all items in the list are Result.Ok then return Result.Ok (or true), else return Result.BadRequest (or false)

I've tried: futureResultList.map(temp => temp.forall(_ == true))

But this code works only when the list contains booleans. It does not work if it contains Result objects (When changing check to _ == Result.Ok)

Upvotes: 2

Views: 1032

Answers (2)

Rohde Fischer
Rohde Fischer

Reputation: 1482

The simplest way to overview such an example is mapping. If you have a List of Result, but need a List of Boolean, then map it. Don't be afraid of mapping multiple times, it's way more readable in the long run :)

val futureResultList: Future[List[Result]] = ???
val futureBooleanList: Future[List[Boolean]] = futureResultList.map(_.map(_ == Result.OK))

val result = futureBooleanList.map(temp => temp.forall(_ == true))

or slightly more concise:

val futureResultList: Future[List[Result]] = ???
val result = futureResultList.map(_.map(_ == Result.OK)
    .forall(_ == true))

and of course as the other people suggest, go directly to checking the equality on the Result object. But mapping is often useful to navigate between types and getting a clearer and more readable code.

Upvotes: 0

Tim
Tim

Reputation: 27356

To return a Boolean you just need to change the predicate in the forall call:

futureResultList.map(_.forall(_ == Result.Ok))

Upvotes: 8

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