Reputation: 79
Trying to execute this code. But i get the above error.
from urllib.request import FancyURLopener
from urllib.request import urlopen
exam = urllib.request.urlopen("192.168.2.2")
print(exam.read)
exam.close()
I expect to open the provided IP address.
Upvotes: 3
Views: 1948
Reputation: 446
from urllib.request import FancyURLopener
from urllib.request import urlopen
exam = urlopen("http://192.168.2.2")
print(exam.read)
exam.close()
Try using urlopen("url")
rather than the full urllib.request.urlopen(url)
.
You need to add http or https on your URL to make this work. Also, check out python requests
, a good alternative to urllib
.
Upvotes: 2