CODEWITHSUNDEEP
pythonquartasgi
Smart Manoj
Smart Manoj

Reputation: 5853

Quart Bad Request syntax or unsupported method

Python 3.7 on windows

When running the sample from quart

from quart import Quart, websocket

app = Quart(__name__)

@app.route('/')
async def hello():
    return 'hello'

@app.websocket('/ws')
async def ws():
    while True:
        await websocket.send('hello')

app.run()

When running http://127.0.0.1:5000/ws, got

Bad Request
Bad request syntax or unsupported method

Upvotes: 1

Views: 744

Answers (1)

Gerard Rozsavolgyi
Gerard Rozsavolgyi

Reputation: 5074

You need a JS client to connect to the WebSocket, not just your browser. Let's call it test-ws.html :

<!DOCTYPE html>
<html>
<body>
    <script>
    let socket = new WebSocket("ws://localhost:5000/ws");

    socket.onmessage = function(event) {
        alert(`Data received: ${event.data}`);
        socket.close();
    };
    </script>
</body>
</html>

(use python3 -m http.server and go to http://127.0.0.1:8000/test-ws.html to test it in your browser)

Upvotes: 2

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