CODEWITHSUNDEEP
c++
user34299
user34299

Reputation: 397

Returning a std::string, converting to char*

I have a function,

std::string ReadShader(const std::string& filePath) {

    std::ifstream stream(filePath);
    std::string line;
    std::stringstream ss;

    while (getline(stream, line)) {

        ss << line << '\n';
    }

    return ss.str();
}

which works when I use these two lines of code,

std::string vertexShaderString = ReadShader("Shader/Vertex_Shader.vs");
const GLchar * vertexShaderSource = vertexShaderString.c_str();

i.e., vertexShaderString contains the expected string, and vertexShaderSource shows the first character of the expected string.

However, when I try a single line of code, viz.,

const GLchar * vertexShaderSource = (ReadShader("Shader/Vertex_Shader.vs")).c_str();

vertexShaderString has a consistent line of characters with a hex code of 0xdd, and vertexShaderSource shows the same 0xdd first character. That is, there is nothing of the expected string in either.

GLchar is an OpenGL typedef for char.

I think there is a C++ basic something I am missing.

Upvotes: 0

Views: 164

Answers (1)

Jonathan Wakely
Jonathan Wakely

Reputation: 171293

Your second version of the code is similar to this:

const GLchar * vertexShaderSource;
{
  std::string tmp = ReadShader("Shader/Vertex_Shader.vs");
  vertexShaderSource = tmp.c_str();
} // tmp is destroyed here

I hope this makes it more obvious that your pointer is referring to the contents of a std::string that has gone out of scope and deallocated its memory.

Upvotes: 4

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