CODEWITHSUNDEEP
pythonstringdirectorysubstring
Isaac Perez
Isaac Perez

Reputation: 590

Replacing parts of a string containing directory paths using Python

I have a large string with potentially many paths in it resembling this structure:

dirA/dirB/a1ed4f3b-a046-4fbf-bb70-0774bd7bfcn

and I need to replace everything before the a1ed4f3b-a046-4fbf-bb70-0774bd7bfcn part of the string with "local/" such that the result will look like this:

local/a1ed4f3b-a046-4fbf-bb70-0774bd7bfcn

The string could contain more than just dirA/dirB/ at the start of the string too.

How can I do this string manipulation in Python?

Upvotes: 0

Views: 189

Answers (4)

B.Gees
B.Gees

Reputation: 1155

Using regular expressions, you can replace everything up to and including the last "/" with "locals/"

import re
s = "dirA/dirB/a1ed4f3b-a046-4fbf-bb70-0774bd7bfcn"
re.sub(r'.*(\/.*)',r'local\1',s)

and you obtain:

'local/a1ed4f3b-a046-4fbf-bb70-0774bd7bfcn'

Upvotes: 3

Jonathan
Jonathan

Reputation: 521

How does this look?

inputstring = 'dirA/dirB/a1ed4f3b-a046-4fbf-bb70-0774bd7bfcn'
filename = os.path.basename(inputstring)
localname =  'local'
os.path.join(localname, filename)

Upvotes: 0

pault
pault

Reputation: 43494

Another alternative is to split the string on "/" and then concatenate "locals/" with the last element of the resultant list.

s = "dirA/dirB/a1ed4f3b-a046-4fbf-bb70-0774bd7bfcn"
print("locals/" + s.split("/")[-1])
#'locals/a1ed4f3b-a046-4fbf-bb70-0774bd7bfcn'

Upvotes: 0

Rakesh
Rakesh

Reputation: 82755

Use os module

Ex:

import os


path = "dirA/dirB/a1ed4f3b-a046-4fbf-bb70-0774bd7bfcn"
print(os.path.join("locals", os.path.basename(path)))

Upvotes: 3

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