CODEWITHSUNDEEP
c#javatemplates
cvlad
cvlad

Reputation: 608

C# Template parameter as a template interface

I am trying to translate this piece of code from Java to C# and I am having trouble finding the correct synthax

Java:

public class MyClass<T extends IMyInterface<T>>

My attempt at translating into C#:

public class MyClass<T, U> where T: IMyInterface<U>

If I do public class MyClass<T> where T: IMyInterface<T> , there is no compile error at the class declaration, but I cannot figure out how to use the class.

More specifically, I have an interface IPoint<T>, which is implemented by class EuclideanPoint:IPoint<EuclideanPoint>. Also, I have a templated class Clusterer<U>, which should not care about the template parameter of the interface, it should only make sure that U is of type IPoint.

Thank you.

Upvotes: 1

Views: 1503

Answers (2)

Jon Skeet
Jon Skeet

Reputation: 1500185

No, the C# equivalent of the Java would just be:

public class MyClass<T> where T : IMyInterface<T>

One type parameter in the Java, one in the C#.

How you use the class will depend on what IMyInterface<T> is and what implements it. For example, if it were IEquatable<T> instead, you could create a MyClass<int> because int implements IEquatable<int>.

Upvotes: 3

Bala R
Bala R

Reputation: 108947

class MyClass<T> where T: IMyInterface<T>

looks good.

If you have

 class MySecondClass : IMyInterface<MySecondClass>
 {

 }

then you can use

 MyClass<MySecondClass> obj = new MyClass<MySecondClass>();

Upvotes: 2

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