Reputation: 1896
In Julia, I've managed to get a boxplot with the following minimal working code:
using Plots
using DataFrames
function boxplot_smaa_similarity(arr_nb_alternative::Vector{Int},
arr_nb_montecarlo::Vector{Int},
nb_criteria::Int, nb_simulations::Int)
# Create a fill dataframe
df = DataFrame(NbAlternative = Int[], NbMonteCarlo = Int[], Similarity = Float64[])
for na in arr_nb_alternative
@show na
for mt in arr_nb_montecarlo
println()
println("...$mt")
append!(df, (NbAlternative=ones(Int, nb_simulations)*na,
NbMonteCarlo=ones(Int, nb_simulations)*mt,
Similarity=rand(Float64, nb_simulations)))
end
end
# Boxplot dataframe data
p = Plots.boxplot(df[:NbMonteCarlo],
df[:Similarity],
group = df[:NbAlternative],
ylims = (0.0, 1.1),
xlabel ="Nb Simulations Monte Carlo",
ylabel = "Similarity",
dpi = 500)
# Save figure to path, do not hesitate to change path if necessary
Plots.savefig("../output/plot_compare_SMAA-TRI-AD_crit$(nb_criteria)"*
"_nb_alternative_$(arr_nb_alternative[1])-$(arr_nb_alternative[end])"*
"_nb_MC$(arr_nb_montecarlo[1])-$(arr_nb_montecarlo[end]).png")
return p
end
boxplot_smaa_similarity([50,100,150], [2,4,6,8,10], 5, 10)
However, the result is not good to me as the three boxplots are overlapping. Is there a fix with Plots.jl
or should I move to PyPlot or another Julia librairy?
Upvotes: 2
Views: 2696
Reputation: 8044
Felipe's comment is correct - you should use StatsPlots.jl, which has all the statistical recipes for Plots.jl. There's a groupedboxplot
recipe which seems not to be in the readme
a = rand(1:5, 100)
b = rand(1:5, 100)
c = randn(100)
using StatsPlots
groupedboxplot(a, c, group = b, bar_width = 0.8)
Upvotes: 4