CODEWITHSUNDEEP
javascript
theJava
theJava

Reputation: 15044

Accessing objects within objects

var data = {
     row: row,
     row2: row2
};

var tableData = [data.row,data.row2];

row objects contains lot of children objects too... now how would i placed my tableData to access each single objects. so it goes like this... 

var tableData = [data.row[1],data.row[2],data.row[3],,data.row2];

Updated Question

var data = [row, row2];

In this case how would i access my row children objects.

Upvotes: 2

Views: 263

Answers (3)

Raynos
Raynos

Reputation: 169531

var data = {key: value, ... };

var tableData = [];
for (var k in data) {
    for (var i = 0, len = data[k].length; i < len; i++)) {
        tableData.push(data[k][i]);
    }
}

Use nested for loops and array.prototype.push

Edit

for (var j = 0, len = data.length;j < len;j++) {
    for (var i = 0, len = data[j].length; i < len; i++)) {
        tableData.push(data[j][i]);
    }
}

You can replace for (var j in data) with for (var j = 0, len = data.length; j < len; j++)

The latter

  • sets j to 0
  • caches the length so you only ask for the length once.
  • Checks that j is not bigger then the amount of elements in your array
  • Increases j when you get to the end of the block.

Upvotes: 1

Hristo
Hristo

Reputation: 46567

How about something like this...

var data = {
    letters : ["a", "b", "c"],
    numbers : ["0", "1", "2", "3"]
};

data.letters; // ["a", "b", "c"]
data.letters[0]; // "a"
data.numbers; // "0", "1", "2", "3"]
data.numbers[2]; // "2"

... or you could try this...

var data = {
    letters : new Array("a", "b", "c"),
    numbers : new Array("0", "1", "2", "3")
};

data.letters; // ["a", "b", "c"]
data.letters[0]; // "a"
data.letters.push("d"); // the array is now ["a", "b", "c"]

data.numbers; // ["0", "1", "2", "3"]
data.numbers[2]; // "2"
data.numbers.pop(); // the array is now ["0", "1", "2"]

For more info on JavaScript arrays, check out these links:

I hope this helps.
Hristo

Upvotes: 1

Billy Moon
Billy Moon

Reputation: 58619

Assign data.row first, then push data.row2, like this:

var tableData = data.row
tableData.push(data.row2)

Upvotes: 1

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