CODEWITHSUNDEEP
django
Trts
Trts

Reputation: 1069

Redirect request to the right view

Django==2.2.2

Urlpatterns:

urlpatterns = [
    re_path(r'^campaigns/$', CampaignsListView.as_view(), name="campaigns_list"),
    re_path(r'^campaigns/(?P<ids>\w+)/$', CampaignsDetailView.as_view(), name="campaigns_detail"),
]

My url:

http://localhost:8000/campaigns/?ids=44174865,44151214,44049374

The problem: This url leads to CampaignsListView rather than to CampaignsDetailView. How can I direct this request to CampaignsDetailView?

Upvotes: 1

Views: 24

Answers (1)

willeM_ Van Onsem
willeM_ Van Onsem

Reputation: 476729

The ?ids=44174865,44151214,44049374 part is not part of the path of a URL, but of the querystring [wiki]. You can not direct to a different view based on the querystring. The content of the querystring is processed into request.GET [Django-doc], a dictionary-like object.

You thus should handle this in the view itself. For example you can filter the list view given there are ids values:

class CampaignsListView(ListView):

    # ...

    def get_queryset(self):
        qs = super().get_queryset()
        ids = request.GET.get('ids')
        if ids:
            try:
                return qs.filter(id__in=map(int, ids.split(',')))
            except ValueError:
                return qs
        return qs

Or you can check if the URL contains a queryset, and then let the CampaignsDetailView do the work, like:

class CampaignsListView(ListView):

    # ...

    def get(self, request, *args, **kwargs):
        if 'ids' in request.GET:
            return CampaignsDetailView.as_view()(request, *args, **kwargs)
        return super().get(request, *args, **kwargs)

Although it looks a bit "ugly".

Upvotes: 1

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