CODEWITHSUNDEEP
pythonpandasnumpydataframe
Jiayu Zhang
Jiayu Zhang

Reputation: 719

Calculate multiple columns by names using python pandas

I have a dataframe similar like this,

cat_A  cat_B  cat_C  cat_D  dog_A  dog_B  dog_C  dog_D
  3      2      4      1      9      8      10     6
 ...
 ...

I knew how to calculate between columns by using column names, like

df['ratio_A'] = df['cat_A']/df['dog_A']

cat_A  cat_B  cat_C  cat_D  dog_A  dog_B  dog_C  dog_D  ratio_A
  3      2      4      1      9      8      10     6      3/9

But when I tried to generate multiple columns by calculate each of those columns, are there any other easier ways to calculate all columns and append new columns by once? Instead of

df['ratio_B'] = df['cat_B']/df['dog_B']

df['ratio_C'] = df['cat_C']/df['dog_C']

df['ratio_D'] = df['cat_D']/df['dog_D']

When the column length become very large it will be a lot of lengthy code to copy and paste. Do I need to create 2 lists like,

l1 = [cat_A, cat_B, cat_C, cat_D], l2= [dog_A, dog_B, dog_C, dog_D]

Then using for loops to implement?

Upvotes: 4

Views: 162

Answers (1)

cs95
cs95

Reputation: 402813

IMO a good practice here would be to work with MultiIndexes instead of flat columns:

df.columns = pd.MultiIndex.from_tuples(map(tuple, df.columns.str.split('_')))
df
  cat          dog          
    A  B  C  D   A  B   C  D
0   3  2  4  1   9  8  10  6

At this point, computing the ratio is very simple courtesy index alignment.

df['cat'] / df['dog']
          A     B    C         D
0  0.333333  0.25  0.4  0.166667

res =  df['cat'] / df['dog']
res.columns = pd.MultiIndex.from_product([['ratio'], res.columns])

pd.concat([df, res], axis=1)
  cat          dog               ratio                     
    A  B  C  D   A  B   C  D         A     B    C         D
0   3  2  4  1   9  8  10  6  0.333333  0.25  0.4  0.166667

Upvotes: 5

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