Reputation: 4687
Hi guys I want to make an array of class objects....so that I can keep on creating as many objects during runtime as and when required I wrote the following code, but its giving me error:
class contact{
public:
string name;//ALL CLASS VARIABLES ARE PUBLIC
int phonenumber;
string address;
contact(){//Constructor
name= NULL;
phonenumber= NULL;
address= NULL;
}
void input_contact_name(string s){//function to take contact name
name=s;
}
void input_contact_number(int x){//function to take contact number
phonenumber=x;
}
void input_contact_address(string add){//function to take contact address
address=add;
}
}
int main(){
contact *d;
d= new contact[200];
string name,add;
int choice;//Variable for switch statement
int phno;
static int i=0;//i is declared as a static int variable
bool flag=false;
cout<<"\tWelcome to the phone Directory\n";//Welcome Message
cout<<"Select :\n1.Add New Contact\n2.Update Existing Contact\n3.Delete an Existing Entry\n4.Display All Contacts\n5.Search for a contact\n6.Exit PhoneBook\n\n\n";//Display all options
cin>>choice;//Input Choice from user
while(!flag){//While Loop Starts
switch(choice){//Switch Loop Starts
case 1:
cout<<"\nEnter The Name\n";
cin>>name;
d[i]->name=name;
cout<<"\nEnter the Phone Number\n";
cin>>phno;
d[i]->input_contact_number(phno);
cout<<"\nEnter the address\n";
cin>>add;
d[i]->input_contact_address(add);
i++;
flag=true;
}
}
return 0;
}
Please can some one out figure out the reason?? Thanks in advance
Upvotes: 2
Views: 22812
Reputation: 62975
Many problems:
string
without using namespace std;
or using std::string;
(or #include <string>
for that matter)cin
and cout
(and <iostream>
)d[i]->
is wrong; d[i]
is a contact&
, not a contact*
, so use .
instead of ->
name= NULL;
and address= NULL;
are nonsensical -- string
is not a pointer type, and already default-constructs to emptyphonenumber= NULL;
is technically valid, but still 'wrong'Also, good lord, use some whitespace in your code.
EDIT (in response to comment): Your constructor should look like:
contact() : phonenumber() { }
Upvotes: 6