Reputation: 3552
I'm trying to parse a txt file that represents a grammar to be used in a recursive descent parser. The txt file would look something like this:
SPRIME ::= Expr eof
Expr ::= Term Expr'
Expr' ::= + Term Expr' | - Term Expr' | e
To isolate the left hand side and split the right hand side into seperate production rules, I take each line and call:
String[] firstSplit = line.split("::=");
String LHS = firstSplit[0];
String productionRules = firstSplit[1].split("|");
However, when I call the second split method, I am not returned an array of the Strings separated by the "|" character, but an array of each indiviudual character on the right hand side, including "|". So for instance, if I was parsing the Expr' rule and printed the productionRules array, it would look like this:
"+"
"Term"
"Expr'"
""
"|"
When what I really want should look like this:
Anyone have any ideas what I'm doing wrong?
Upvotes: 29
Views: 27081
Reputation: 340055
The parameter to String.split()
is a regular expression, and the vertical bar character is special.
Try escaping it with a backslash:
String productionRules = firstSplit[1].split("\\|");
NB: two backslashes are required, since the backslash character itself is special within string literals.
Upvotes: 71
Reputation: 63708
You need to escape pipe(|
) symbol which is a regex
OR
operator .
String productionRules = firstSplit[1].split("\\|");
or
String productionRules = firstSplit[1].split(Pattern.quote("|"));
Upvotes: 14
Reputation: 13748
The pipe character is the regex operator for "or". What you want is
String productionRules = firstSplit[1].split("\\|");
which tells it to look for an actual pipe character.
Upvotes: 7
Reputation: 4469
Since split
takes a regex as argument you have to escape all non-intended regex symbols.
Upvotes: 26