CODEWITHSUNDEEP
ruby-on-railsdatetime
Tilendor
Tilendor

Reputation: 48903

How do I get the number of seconds between two DateTimes in Ruby on Rails

I've got code that does time tracking for employees. It creates a counter to show the employee how long they have been clocked in for.

This is the current code:

  start_time = Time.parse(self.settings.first_clock_in)
  total_seconds = Time.now - start_time
  hours = (total_seconds/ 3600).to_i
  minutes = ((total_seconds % 3600) / 60).to_i
  seconds = ((total_seconds % 3600) % 60).to_i

This works fine. But because Time is limited to the range of 1970 - 2038 we are trying to replace all Time uses with DateTimes. I can't figure out how to get the number of seconds between two DateTimes. Subtracting them yields a Rational which I don't know how to interpret, whereas subtracting Times yields the difference in seconds.

NOTE: Since Ruby 1.9.2, the hard limit of Time is removed. However, Time is optimized for values between 1823-11-12 and 2116-02-20.

Upvotes: 86

Views: 84212

Answers (7)

Amin Ariana
Amin Ariana

Reputation: 4805

Time

No need to rely on fractions or helper functions. It's much simpler than that. Time itself is integer underneath. Here's the Ruby way:

stop.to_i - start.to_i

Example:

#!ruby
> start = Time.now
 => 2016-06-21 14:55:36 -0700
> stop = start + 5.seconds
 => 2016-06-21 14:55:41 -0700
> stop.to_i - start.to_i
 => 5

DateTime

DateTime on the other hand returns a Rational after subtraction, which is a fraction of a day. So you can still do:

((dt2 - dt1) * 24 * 60 * 60).to_i

or

((dt2 - dt2) * 86400).to_i

By example:

#!ruby
> dt1 = DateTime.new(2024, 3, 11, 12, 0, 0)
> dt2 = DateTime.new(2024, 3, 11, 12, 30, 0)
> (dt2 - dt1)
 => (1/48)
> (dt2 - dt1).class
 => Rational
> difference_in_seconds = ((dt2 - dt1) * 24 * 60 * 60).to_i
 => 1800

Upvotes: 28

Avram Dorfman
Avram Dorfman

Reputation: 557

Or, more readably:

diff = datetime_1 - datetime_2
diff * 1.days # => difference in seconds; requires Ruby on Rails

Note, what you or some other searchers might really be looking for is this:

diff = datetime_1 - datetime_2
Date.day_fraction_to_time(diff) # => [h, m, s, frac_s]

Upvotes: 54

ramya
ramya

Reputation: 275

Define a Ruby function like this,

def time_diff(start_time, end_time)
  seconds_diff = (start_time - end_time).to_i.abs

  days = seconds_diff / 86400 
  seconds_diff -= days * 86400

  hours = seconds_diff / 3600  
  seconds_diff -= hours * 3600

  minutes = seconds_diff / 60
  seconds_diff -= minutes * 60

  seconds = seconds_diff

  "#{days} Days #{hours} Hrs #{minutes} Min #{seconds} Sec"
 end

And Call this function,

time_diff(Time.now, Time.now-4.days-2.hours-1.minutes-53.seconds)

Upvotes: 1

Francois
Francois

Reputation: 1510

there's a method made for that:

Time.now.minus_with_coercion(10.seconds.ago)

equals 10.

Source: http://apidock.com/rails/Time/minus_with_coercion

Hope I helped.

Upvotes: 1

Som Poddar
Som Poddar

Reputation: 1451

I am using ruby-2.1.4 and for me the following worked

Time.now - Time.new(2014,11,05,17,30,0)

gave me the time difference in seconds

reference: ruby doc

Upvotes: 8

Luke
Luke

Reputation: 4431

You can convert them to floats with to_f, though this will incur the usual loss of precision associated with floats. If you're just casting to an integer for whole seconds it shouldn't be big enough to be a worry.

The results are in seconds:

>> end_time.to_f - start_time.to_f
=> 7.39954495429993

>> (end_time.to_f - start_time.to_f).to_i
=> 7

Otherwise, you could look at using to_formatted_s on the DateTime object and seeing if you can coax the output into something the Decimal class will accept, or just formatting it as plain Unix time as a string and calling to_i on that.

Upvotes: 34

David Ma
David Ma

Reputation: 1353

Subtracting two DateTimes returns the elapsed time in days, so you could just do:

elapsed_seconds = ((end_time - start_time) * 24 * 60 * 60).to_i

Upvotes: 98

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